Explain how the measured cell potentials would be affected if the concentration of the Cu2+(0.1 M)/Cu half-cell was actually 0.2 M.ProcedurePipet 1 mL of the 0.1 M Cu(NO3)2 solution (Solution 1) from the Zn2+(0.1 M)/Zn half-cell into a 50 mL volumetric flask and dilute to the mark with deionized water. Pour this diluted solution (Solution 2) into a 50 mL beaker.Pipet 1 mL of Solution 2 into a 50 mL volumetric flask and dilute to the mark with deionized water. Pour this diluted solution (Solution 3) into a 50 mL beaker. Repeat using Solution 3 to prepare Solution 4. Measure the cell potential for each of the three galvanic cells that can be made by pairing the Zn2+(0.1 M)/Zn half-cell with the half-cells containing Solutions 2–4 and the copper electrode. Potential (V)Solution 20.051Solution 30.106Solution 40.148

From the above procedure we understand that the concentration of copper ions in the solution…

Answered: Potential (V) Solution 2 0.051 Solution…

Chemistry: Matter and Change

1st Edition

ISBN:9780078746376

Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom

Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom

Chapter14: Mixtures And Solutions

Section14.3: Factors Affecting Solvation

Problem 42SSC

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Question

Explain how the measured cell potentials would be affected if the concentration of the Cu2+(0.1 M)/Cu half-cell was actually 0.2 M.

Procedure

Pipet 1 mL of the 0.1 M Cu(NO3)2 solution (Solution 1) from the Zn²⁺(0.1 M)/Zn half-cell into a 50 mL volumetric flask and dilute to the mark with deionized water. Pour this diluted solution (Solution 2) into a 50 mL beaker.
Pipet 1 mL of Solution 2 into a 50 mL volumetric flask and dilute to the mark with deionized water. Pour this diluted solution (Solution 3) into a 50 mL beaker. Repeat using Solution 3 to prepare Solution 4.
Measure the cell potential for each of the three galvanic cells that can be made by pairing the Zn²⁺(0.1 M)/Zn half-cell with the half-cells containing Solutions 2–4 and the copper electrode.

Potential (V)
Solution 2
0.051
Solution 3
0.106
Solution 4
0.148

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