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Population Growth
R and K Selection
R and K selection are concepts in ecology used to describe traits in the fluctuation of a population or population dynamics. For example, they describe the life-association traits between parent and offspring, such as quantity or number of young ones born at a time, quality of parental care, the age to maturity, and reproductive effort.
If population growth is assumed to be density dependent in all four populations, what will happen to these populations sometime after generation 10?
1.
2. Rate of population growth will decrease.
3. Rate of population growth will remain the same.
4. All populations will follow the curve of population
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- I need help in table 2 & 3 please Table 1 Phenotype O E O-E (O-E)^2 (O-E)^2 /E Disease, Male 304 433.875 129.875 16789.68 38.69 Disease, Female 267 433.875 166.875 26855.01 61.89 WT, Male 285 144.625 140.375 19705.14 136.25 WT, Female 301 144.625 156.375 24453.15 156.37 Total 1157 1157 393.20 DF 3 p-value 7.84 Expected progencies as per SLR MOI’s = 1:1 for both male and female Phenotype O E O-E (O-E)^2 (O-E)^2 /E Disease, Male 304 289.25 14.75 217.56 0.75 Disease, Female 267 289.25 22.25 495.06 1.85 WT, Male 285 289.25 4.25 18.06 0.06 WT, Female 301 289.25 11.75 138.06 0.46 Total 1157 1157 3.12 DF 3 p-value 7.84 Progenies are following SR MOI’s that parents have genotypes and progenies in ratio 1:1 In Table 2,…-ral Biology mmer Session 1 2021/BIO 100/D1/ Assessments/ BIO 100 Test- Genetics Sickle cell anemia is an inherited red blood cell disorder in which there are not enough healthy red blood cells to carry oxygen throughout the body. The allele that causes sickle-cell anemia is autosomal recessive (s), and the dominant allele can be represented by S. How many offspring will be affected by the disorder if the mother is a carrier, and the a. father appears to be normal? (Include the gender) b. How many will become carriers? (include the gender) A BI 四 四 II I!!Trivla Game Show _Make Your Own Tri ngston.schoology.com/common-assessment-delivery/start/4789189591?action=onresume&submissionld=463322566 Dillon WF g Aa v Done In guinea pigs, black hair (B) is dominant to white hair (b) and rough hair (R) is dominant to smooth hair (r). What are all the possible genotypes of a guinea pig that has black, rough hair? (Select all that apply.) O BBRR BBRr BBrr BBRR BbRr O bbRR O bbRr O bbrr O Black O White O Rough OSmooth O Rough O Smooth
- Edio | Course Student Lesson Using the letter T to represent t x + days/1089940/lessons/1533883/variants/2273231/take/14/ O Alert 1 of 1: Instructional Technology Subsidy Úp. DISMISS * Practice MULTIPLE CHOICE Using the letter T to represent the trait, what is the genotype for individual 7? TT TE it is impossible to determine from this picture Atempe t of 2 683838886 0888.o S of & Total Questions Answered A Changes Saund 21°F Sunnyab H Q9. Who's gonna take you home tonight? There has been a mix up in the maternity ward. The babies have managed to remove their wrist bands. On their wrist bands are their blood groups and names. and art Billy Smith Blood group:A Sarah Chadwick Blood group:AB Imran Ahmed Blood group:B Johnny Honest Blood group:0 nislax 80 Complete the table to match each parent to their baby by indicating the parental genotypes using the symbols IA, IB, and i, and then the name of the baby that belongs to each set of moo parents. Consider one blood type might have more than one genotype. ever Parental Blood groups Parents Genotype Baby Blood Group O and O si grappo AB and O 196² A and O AB and A Completed forms to be made available for external moderation.(19) WhatsApp 0 (542) H.E.R. - Changes X Why is it not possible X al%20School/OneDrive/Documents/Grade%2012%20variation%20and%20evolution%20 (D Page view A Read aloud V Draw Hig ii). iii). 13) 4. Sickle cell anemia is a favorable mutation. There is only one amino acid dillerent in Sickle hemoglobin (S) as compared with normal adult hemoglobin (A). Persons with sickle cell trait (AS) are able to survive in malarious areas. i) A couple each having sickle cell trait have five children. What is the probability thas they will have a child with sickle cell disease?
- ard | Climax-Scotts VA e Genes: The Heredity Code: Mas MVA High School Curriculum S x + f1.app.edmentum.com/assessments-delivery/ua/mt/launch/49419269/858302444/aHR0cHM6Ly9mMS5hcHAUZWRtZW50dW0uY29tL2xlYXJuZXItdWkvc2V... A cation 4▾ Seesaw e Edmentum® Learni... Genius Next O Genes: The Heredity Code: Mastery Test Select the correct answer from each drop-down menu. Offspring inherit genes from their parents, and these genes determine their physical characteristics. According to the law of a heterozygous organism has about a allele. entum. All rights reserved. Search assortment genetics segregation Reset Next chance of producing gametes with the recessive SubmitCan someone tell me if the answer is 50% or 25%?Note there are no cells on this panel that have a double dose (homozygous) of the K antigen. Which of the following statements is true regarding the K+k- phenotype? Question 6 options: A) The phenotype is rare due to the high prevalence of the k antigen in the population. B) The phenotype is uncommon but does occur in about 10% of the population. C) The phenotype occurs in about 50% of the population. D) Although the phenotype is not represented on this antibody panel, it is fairly common in the population.
- is this 80% x 250？？？Use keyboard only to enter your answer below. ALL WORKING MUST BE SHOWN Problem 1) mutation in a gene on chromosome 15 that codes for an enzyme. The disease is an inherited autosomal recessive condition which is Tay-Sachs disease is caused by loss of function found amongst Ashkenazi Jews of Central European origin. In this population, 3 in 5,200 children are born with the disease. What proportion of the population are carriers (heterozygotes) for this disease?W O () ENG 9:37 am O GENBIO-1ST-SEM-MIDTERN X 9 Schoology G karyotype of a certain huma x 6 BigBlueButton - GNBIO Messenger My Questions | bartleby + A app.schoology.com/common-assessment-delivery/start/5385424680?action=Donresume&submissionld=643190401 The diagram below shows a karyotype of a certain human. 8. 10 11 12 13 14 15 16 17 18 19 21 22 X Y Based on the karyotype, which of the following statements is most likely true? O The individual has a genetic condition caused by a nondisjunction event. The individual has a genetic condition caused by the X and Y chromosomes being different sizes. O The individual has a genetic condition caused by a chromosomal duplication. O The individual has a genetic condition caused chromosomes number one being different sizes. GENBIO-1ST-SEM-.pdf O 245180335_56899...jpg Show all ... TID N DAD × IDD . I ID.