Solve both show all steps and solutions Find the value of the input torque on the crank-shaftmechanism in following Figure. The centers of gravityof link 2, 3 and 4 are at G₂, G3 and G4 respectively. Themasses and moments of inertia of the links are: m₂=2kg, m3 =0.5 kg,m4 = 0.5 kg, IG2 = 0.001 kg m², IG3 = 0.01 kg m² and IG4= 0.002 kg m². It is known that: O₂A = 3 cm, AB = 7cm, AG3 = 2 cm, 0₂ = 60°, ₂ =-20 rad/s², a₂ = -100rad/s² and that external force P4 has a magnitude of 98N. consider 03 =338.2° and the following accelerationsfor links 3 and 4: a3 = -250.26^i- 849:45^j cm/s², α3 =A3174:44 rad/ s², aG4 = -25.45^i cm/s², α4 = 0.a4A2Mo00₂=G₂G₂3B=G4P₁ To carry out dynamic force analysis of the four-barmechanism shown in the figure. It is required to findthe inertial radius of the links.Where w220rad /s (cw), a2 = 160 rad/s2 (cw)OA=250mm,OG2=110mm,BC=300mm,AG3=150mm,OC=550mm, ĐAOC = 60°The masses & mass moment of inertia of the variousmembers are:Link234F₁2 AMass, m20.7kg9.66kg23.47kg3F₁34G3α31(a) Scale: 1 cm = 10 cmsMMI (IG, Kgm2)0.018720.011050.0277ABAAB=300mm,CG4=140mm,b"YABAA AaABb'AccelerationpolygonScale1 cm = 20 m/sec²Note: The listed scales are not perfectly correct,Consider the following values to find out the correctscale of acceleration polygon.V₁=250×20; 5m/s, VB = 4 m/s, VBA = 4.75 m/sa = 250×20²; 100m/s², a = 250×160; 40m/s²

Itis asked to carry out dynamics analysis of the mechanics given below

Find the value of the input torque on the crank-shaft mechanism in following Figure. The centers of gravity of link 2, 3 and 4 are at G₂, G3 and G4 respectively. The masses and moments of inertia of the links are: m₂=2 kg, m3 =0.5 kg, m4 0.5 kg, IG2 = 0.001 kg m², IG3 = 0.01 kg m² and IG4 = 0.002 kg m². It is known that: O₂A = 3 cm, AB = 7 cm, AG3 = 2 cm, 0₂ = 60°, ₂ =-20 rad/s², a₂ = -100 rad/s² and that external force P4 has a magnitude of 98 N. consider 03 =338.2° and the following accelerations for links 3 and 4: ag3 = -250.26^i- 849:45^j cm/s², 174:44 rad/ s², aG4 = -25.45^i cm/s², a4 = 0. A = α3 =

Find the value of the input torque on the crank-shaft mechanism in following Figure. The centers of gravity of link 2, 3 and 4 are at G₂, G3 and G4 respectively. The masses and moments of inertia of the links are: m₂=2 kg, m3 =0.5 kg, m4 0.5 kg, IG2 = 0.001 kg m², IG3 = 0.01 kg m² and IG4 = 0.002 kg m². It is known that: O₂A = 3 cm, AB = 7 cm, AG3 = 2 cm, 0₂ = 60°, ₂ =-20 rad/s², a₂ = -100 rad/s² and that external force P4 has a magnitude of 98 N. consider 03 =338.2° and the following accelerations for links 3 and 4: ag3 = -250.26^i- 849:45^j cm/s², 174:44 rad/ s², aG4 = -25.45^i cm/s², a4 = 0. A = α3 =

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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To carry out dynamic force analysis of the four-bar mechanism shown in the figure. It is required to find the inertial radius of the links. Where w220rad /s (cw), a2 = 160 rad/s2 (cw) OA= 250mm, OG2= 110mm, BC=300mm, AG3=150mm, OC=550mm, ĐAOC = 60° The masses & mass moment of inertia of the various members are: Link 2 3 4 F₁2 A Mass, m 20.7kg 9.66kg 23.47kg F₁3 G3 α3 1 (a) Scale: 1 cm = 10 cms F₁4 MMI (IG, Kgm2) 0.01872 0.01105 0.0277 t ABA b" AB=300mm, CG4=140mm, 84 Y ABA AA a AB Acceleration polygon Scale 1 cm = 20 m/sec² Note: The listed scales are not perfectly correct, Consider the following values to find out the correct scale of acceleration polygon. V₁ = 250×20; 5m/s, VB = 4 m/s, VBA=4.75 m/s a' = 250×20²; 100m/s², a = 250×160; 40m/s²
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