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please help me with this c++ code, and I did not understand why the output is x=10 y=20. Please explain to me. #include using namespace std; class Test { private: int x; int y; public: Test(int x = 0, int y = 0) { this->x = x; this->y = y; } Test &setX(int a) { x = a; return *this; } Test &setY(int b) { y = b; return *this; } void print() { cout << "x = " << x << " y = " << y << endl; } }; int main() { Test obj1(5, 5); // Chained function calls. All calls modify the same object // as the same object is returned by reference obj1.setX(10).setY(20); obj1.print(); return 0; }

please help me with this c++ code, and I did not understand why the output is x=10 y=20. Please explain to me. #include using namespace std; class Test { private: int x; int y; public: Test(int x = 0, int y = 0) { this->x = x; this->y = y; } Test &setX(int a) { x = a; return *this; } Test &setY(int b) { y = b; return *this; } void print() { cout << "x = " << x << " y = " << y << endl; } }; int main() { Test obj1(5, 5); // Chained function calls. All calls modify the same object // as the same object is returned by reference obj1.setX(10).setY(20); obj1.print(); return 0; }

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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please help me with this c++ code, and I did not understand why the output is x=10 y=20. Please explain to me. 

#include<iostream>
using namespace std;
  
class Test
{
private:
  int x;
  int y;
public:
  Test(int x = 0, int y = 0) { this->x = x; this->y = y; }
  Test &setX(int a) { x = a; return *this; }
  Test &setY(int b) { y = b; return *this; }
  void print() { cout << "x = " << x << " y = " << y << endl; }
};
  
int main()
{
  Test obj1(5, 5);
  
  // Chained function calls.  All calls modify the same object
  // as the same object is returned by reference
  obj1.setX(10).setY(20);
  
  obj1.print();
  return 0;
}
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