PLEASE EXPLAIN THE PROBLEM BEOW AND THE ANSWER Given the following structs, how many bytes would a single A take up? Answer in decimal only. struct A { char* str1; char ch; int* i, j; B a, b, c; }; struct B { A* a; }; Answer =
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PLEASE EXPLAIN THE PROBLEM BEOW AND THE ANSWER
Given the following structs, how many bytes would a single A take up? Answer in decimal only.
struct A {
char* str1;
char ch;
int* i, j;
B a, b, c;
};
struct B {
A* a;
};
Answer =
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- Floating-point struct Part 1 Define a struct Single that describes the bit layout for a single-precision floating-point number. You should be able to compile this definition but there is no code to run yet. This will be done in the next step. You will need to use bit fields in the struct. Notice that you need to consider little-endian vs. big-endian. Your submission should answer the following questions about this program: Why does endian matter here and not for part 2? Printing floating-point parts Part 2 Define a method void printSingle(float f) that will print the parts of the floating-point number as distinct values. A typical output should look like: For value 3.5, sign=0 exp =128, fraction=11000000000000000000000 To place the float into the struct, use a pointer cast or a union. For example, using a pointer cast to interpret the bits of a floating-point number as an integer, you could say int i; *(float *)&i = f; To print a floating-point number in printf, you typically use %f.…CFG: Example 1 • Draw the CFG for the following code: int f(int n){ } int m = n* n; if (n < 0) else return 0; return m;int x1 = 66; int y1 = 39; int d; _asm { } mov EAX, X1; mov EBX, y1; push EAX; push EBX; pop ECX mov d, ECX; What is d in decimal format?
- #include <stdio.h>void cubeByReference( int *nPtr ); // function prototypeint main( void ){ int number = 5; // initialize number printf("The original value of number is %d", number ); // pass address of number to cubeByReference cubeByReference( &number ); printf("\nThe new value of number is %d\n", number );} // end main void cubeByReference( int *nPtr ){ *nPtr = *nPtr* *nPtr* *nPtr;} passing argument by reference - We modify the code above 1- define a second argument (example "int number2 = 9") and a pointer to it 2- define a second function (addByReference) that adds number2 to number - passing both arguments by reference 3- print-out the result (that is in number) Upload the output and .c codeint func(int a, int b) { return (acode this:C++ program The Lo Shu Magic Square is a grid with three rows and three columns that has the following properties: • The grid contains the numbers 1 through 9 exactly.• The sum of each row, each column, and each diagonal all add up to the same number. This is shown in Figure 1: Figure 1: Lo Shu Magic SquareWrite a Boolean function isMagicSquare that accepts a two-dimenstional 3 × 3 array as an argument and returns true if it determines it is a Lo Shu Magic Square and false if it is not.Q1/ False or True 1- Assembler translates a program written in a low-level language to machine language. 2- C++ used to create system applications. 3- float is acceptable identifier. 4- int T=2.5; 5- The sizeof float is 4 bits. 6- The output of this program is 2. int main() { int i=8, j=3; float div; div= i/j; cout<< div;Matrix Problem Code this in C Write a program that reads two matrices of integers. It then generates the sum, difference, and product of the two matrices. The sum of the two matrices of the same size is a matrix with elements that are the sums of the corresponding elements of the two given matrices. Addition is not defined for matrices of different sizes. If A and B are matrices of the same size, then we define subtraction as follows: A – B = A + (-B). Thus, to subtract matrix B from matrix A, we simply subtract corresponding elements. To multiply a matrix by another matrix we need to do the "dot product" of rows and columns. The "Dot Product" is where we multiply matching members, then sum up: (1, 2, 3) • (7, 9, 11) = 1×7 + 2×9 + 3×11 = 58 We match the 1st members (1 and 7), multiply them, likewise for the 2nd members (2 and 9) and the 3rd members (3 and 11), and finally sum them up. Use the following definitions:#define ROW 6#define COL 6void add(int matrixResult[][COL],int…int main(int argc, char **argv) { float *rainfall; float rain_today; // rainfall has been dynamically allocated space for a floating point number. // Both rainfall and rain today have been initialized in hidden code. // Assign the amount in rain_today to the space rainfall points to. return 0; }The following data structure is declared in a C/C++ program: struct DATA { int a; char b; short c; int d; char e; } Given: int = 4 bytes, char = 1 byte, short = 2 bytes, draw the most likely arrangement of data in memory for each of the following situations: a) On an Intel Architecture computer running the Linux OS b) On an Intel Architecture computer running the MS Windows OS c) On a computer that imposes 4-byte word alignmentFor the C++ program show on the next page, answer the questions that follow. The names g, j, x, and y are declared multiple times. Distinguish uses of these names using line numbers where they were declared as subscripts. a. At point A in the program, what names are in scope? b. At point A in the program, what variables are live? c. At point B in the program, what names are in scope? d. At point B in the program, what variables are live?SEE MORE QUESTIONS