Please explain the number of signals and the integration that is observed in the 1H NMR spectrum for the major product of the reaction from question 6. - Focus on the alkyl protons, in particular those two methylene (CH2) groups 88¹H NMR - Number of signals*)Aromatic protons3 signals7O)¹H NMR - Intergration*)Aromatic protonsIntegration: 2:2:17-CO6·LO5-LO54PPM4PPMAlkyl protons: 6 signalsOH proton: 1 signal323Alkyl protons and OH proton -Integration:1:1:1:1:1:1:1-~121*) Two of the signals for the aromatic protons happen to have a very similar chemical shift.00

The proton NMR signal ratios and the peak integration as well as the peak values can give a fair…

Please explain the number of signals and the integration that is observed in the 1H NMR spectrum for the major product of the reaction from question 6. - Focus on the alkyl protons, in particular those two methylene (CH2) groups

Please explain the number of signals and the integration that is observed in the 1H NMR spectrum for the major product of the reaction from question 6. - Focus on the alkyl protons, in particular those two methylene (CH2) groups

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter13: Structure Determination: Nuclear Magnetic Resonance Spectroscopy

Section13.8: More Complex Spin–spin Splitting Patterns

Problem 15P: 3-Bromo-1-phenyl-1-propene shows a complex NMR spectrum in which the vinylic proton at C2 is coupled...

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Question

Please explain the number of signals and the integration that is observed in the ¹H NMR spectrum for the major product of the reaction from question 6. - Focus on the alkyl protons, in particular those two methylene (CH₂) groups

8
8
¹H NMR - Number of signals*)
Aromatic protons
3 signals
7
O)
¹H NMR - Intergration*)
Aromatic protons
Integration: 2:2:1
7
-CO
6
·LO
5
-LO
5
4
PPM
4
PPM
Alkyl protons: 6 signals
OH proton: 1 signal
3
2
3
Alkyl protons and OH proton -
Integration:1:1:1:1:1:1:1
-~
1
2
1
*) Two of the signals for the aromatic protons happen to have a very similar chemical shift.
0
0

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