Perform the Q-test on the following NaOH molarities: 0.1110 M 0.1115 M 0.1007 M 0.1016 M Select all correct answers. O Keep 0.1115 M OQN- 0.08 O Discard 0.1007 M 2Q lo - 0.05 Range - 0.0100M
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- Calculate [OH] for each of the following solutions Y Part A [H]=4.2x10-3 M Express the molarity to two significant digits. [OH |- Submit Part B 15] ΑΣΦΑ Request Answer Pearson ? Review | Con MProcedure: 1) Preparation of 100 mL 0.1N Na2CO3 2) How much is the molarity of the prepared solution 3) Dilute the solution to get 100 ml 0.01 N. 4) How much the Molarity of the diluted solution. M.wt of Na2CO3 = 106 g mol-1 Eq.wt = 106 / 2 = 53 g eq1 %3D Every 53 g in 1000 ml How much?(x) » in 100 mL → to give 0.1 N 53 x 100 x 0.1 X = 0.53 g 1000 x 1 : weigh 0.53 g Na2CO3 place it in a beaker, add about 30-50 ml distilled water , stir well. Transfer the solution to 100 ml volumetric flask, then fill to the mark with distilled water to get 0.1 N solution. • Put your results and your answers in the following table : Wt. NażCO3 (g) Normality N eq L-1 Molarity M mol L-1 53 ? 0.53 After dilution 0.01Question. Determination of percent water (%H₂O) in hydrated FeSO4nH₂O is demonstrated in General Chemistry Laboratory (I), Chem. 105. The following table contains the results collected from the students groups. 1 2 3 4 5 6 (a) Calculate the average number of water molecules (b) %H₂O in each sample. 3.38 3.47 3.35 3.40 3.44 3.41 1.4 1.35 1.35 1.44 1.49 1.39 Mass of water (g) Moles of water Moles FeSO4 11= Moles H₂O Mole FeSO Average n % water in hydrated salt (wt/wt) Hint: Atomic mass: Fe = 56 g/mol; O = 16 g/mol; H = 1.0 g/mol; S = 32 g/mol.
- Esc 2 What is the concentration of a solution made with 0.245 moles of KOH in 400.0 mL of solution? 1 F1 ! + A 4x Q N Bi F2 NO @ 2 W S Alt X F3 # 3 JL E F4 D 14 C $ 4 F5 R F ► 11 % 5 V F6 A T G ^ (0 F7 6 B Y H F8 & 7 2 DELL U N F9 * S 8 J F10 ( 3 9 F11 J K O A ) O F12 L Alt PrtScr P 7 BU +/- 4 1 Inse- [ VER ?la a laccd sign in - X ||| ctrl shift T tab O CHEMICAL REACTIONS Calculating molarity using solute moles caps lock ILION McGraw-Hill Ec X A ALEKS - Shusha X https://www-awu.aleks.com/alekscgi/x/lsl.exe/10_u-IgNslkr7j8P3jH-IvUrTNdLZh5A8CnG03PBGuXr8iCPa7ZMmym 0 lion x360 fn ALEKS μmol L A chemist prepares a solution of sodium hyposulfate (Na₂S₂O3) by measuring out 200. μmol of sodium hyposulfate into a 400. mL volumetric flask and filling the flask to the mark with water. Explanation esc Calculate the concentration in μmol/L of the chemist's sodium hyposulfate solution. Be sure your answer has the correct number of significant digits. →1 1 Z X Type here to search hp Check 2 x10 Graw # 3 X Xx WIL S alt ** 4 C S O % 40 5 V A- G B f7 4+ & 19 ALEKS 7 H hip 18 X IAA N 8 McGraw-Hill Ex A ALEKS-Shush x+ 95T1680XLLcyeOLT... A © 2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Acce 6:25 PM a 7/22/202 9 K M ho P f12 87°F Qo insert 1/5 [ alt prt sc 1 G 2 backspac pause…What is the concentration of a solution made by diluting 85 mL of 6.0 M HCl to a final volume of 750 mL? concentration: J $ 4 R F F4 V % 5 T G B ^ 6 MacBook Air Y H & 7 N B U J * 8 M MOSISO DII FB K 9 H DD FO O ) O L command A F10 P A. 1. option 4 F11 L ? + f F12 M delete ret
- TITRIMETRIC DATA SAMPLE: CANE VINEGAR % acidity in label: 4.5% %purity of KHP: 99.80% FORMULA WEIGHT of KHP: 204.22 g/mol STANDARDIZATION OF NaOH SOLUTION TRIAL 1 TRIAL 2 TRIAL 3 Weight of KHP, g 0.1012 0.1004 0.09987 Initial volume of NaOH, mL 5.00 10.01 Final volume of NaOH, mL 4.95 9.99 14.93 Molarity of NaOH Average Molarity of NaOH ANALYSIS OF ACETIC ACID IN A VINEGAR SAMPLE TRIAL 1 TRIAL 2 TRIAL 3 Volume of vinegar, mL Initial volume of NaOH, mL 1.00 1.00 1.00 14.98 22.90 30.87 Final volume of NaOH, mL 22.84 30.77 38.75 Molarity of acetic acid Average molarity of acetic acid ANALYSIS OF CARBONIC ACID IN A SODA SAMPLE TRIAL 1 TRIAL 2 TRIAL 3 Volume of soda, mL 20.0 20.0 20.0 Initial volume of NaOH, mL 20.20 22.05 23.93 Final volume of NaOH, mL 22.03 23.89 25.8 Molarity of carbonic acid Average molarity of carbonic acidShould be 3 answers in total. Will thumbs up! Next the student conducts two different runs: In RUN 1, 10.0 mL of 5.00 M NAOH is combined with 10.0 mL of 0.010 M CO and 80.0 mL of wate In RUN 2, 20.0 mL of 5.00 M NAOH is combined with 10.0 mL of 0.010 M CO and 70.0 mL of wate The following plots were obtained for each of the runs: [crystal orange] vs time (RUN 1) In[crystal orange] vs time (RUN 1) 0.0012 0.001 -2 y--0.4463x- 7.3334 y =-0.0002x + 0.0007 R- 0.6565 R = 0.893 0.0008 4 0.0006 -6 0.0004 -8 0.0002 0.0002 -12 time (hr) time (hr) 1/[crystal orange] vs time (RUN 1) 1/[crystal orange] vs time (RUN 2) 12000 25000 10000 20000 8000 15000 6000 y = 2000x + 1000 R =1 10000 y 4000x + 1000 R =1 4000 2000 5000 time (hr) time (hr) Figure 4. Kinetic traces for the reaction between crystal orange and sodium hydroxide. What is the order with respect to CO? | Select ] What is the order with respect to NaOH? | Select ] What is the value of the averaged rate constant for the reaction above? Give…Question . Determination of percent water (%H₂O) in hydrated FeSO4nH₂O is demonstrated in General Chemistry Laboratory (I), Chem. 105. The following table contains the results collected from the students groups. 1 23 2 4 5 6 3.38 3.47 3.35 3.40 3.44 3.41 1.4 1.35 1.35 1.44 1.49 1.39 Q1) Assume MM of FeSO4 is 152 g/mol. What is the average number of water molecules in the samples? Q2) What is the average % water (wt/wt) for all samples? n= Moles H₂O Mole FeSO, Average n Q3) What is the average number of moles of water for all samples? Q4) What is the correct formula of the salt? % water in hydrated salt (ww/wt)
- Help )) 32% Mon 1:12 AM dix-d.pdf AC=8935a868521ec4cdala6e89069b89458#10001 6 o I Review I Constants I Periodic Table Calculate the concentration of CIO, at equilibrium if the initial concentration of HCIO2 is 2.17x10-2 M. Express the molarity to three significant digits. 响 AX中 [CIO2 | = M Submit Request Answer Part C Calculate tm concentration of HC1O2 at equilibrium if the initial concentration of HC1O2 is 2.17x10-2 M . Express the molarity to three significant digits. ? [HCIO2] = P Pearson Pearson Education Inc. All rights reserved. Terms of Use | Privacy Policy Permissions | Contact Us | 895 102 W tv MacBook Air 圓 國(A=)=0.0025 mL = 110 x 10-4 X² (0.025 +0.0258) = 0.0492 = 14 +Tog LOH]- 1.4 x 10-4 0-0492 = 14-523 = 8.27 = 7-14×10" = x², 00492 3. If 50.00 mL of 1.00 M HC₂H₂O₂ (K = 1.8 x 105) is titrated with 1.00 M NaOH. What is the pH of the solution after the following volumes of NaOH have been added? a) 0.00 mL b) 25.00 mL c) 49.90 mL d) 50.10 mL3:59 PM Wed Mar 15 ... ap here or pull up for additional resources Question 74 of 75 A 25.0 mL solution of HNO3 is neutralized with 16.5 mL of 0.250 M Ba(OH)2. What is the concentration of the original HNO3 solution? 1 4 7 +/- 1 M 2 3 5 6 8 9 O LTE 32% Submit XC с x 100