Pentane is a good fuel that burns well in oxygen. C5H12(1) + 802(g) → 5CO2(g) + 6H2O(1) Calculate the enthalpy change for this reaction given the following enthalpies of formation: AH / kJ mol C;H12(1) = -147 CO2(g) = –394 H2O(I) = -286 %3D %3D

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section5.7: Enthalpy Calculations
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Calculate the enthalpy change for this reaction using the enthalpies of formation shown.
TICL(s) + 2Mg(s)→ 2M9CL2(s) + Ti(s)
A;H / kJ mol TiCl«(s) = -912 MgCl2(s) = –642
%3D
Transcribed Image Text:Calculate the enthalpy change for this reaction using the enthalpies of formation shown. TICL(s) + 2Mg(s)→ 2M9CL2(s) + Ti(s) A;H / kJ mol TiCl«(s) = -912 MgCl2(s) = –642 %3D
Pentane is a good fuel that burns well in oxygen. C;H12(1) + 802(g) → 5CO2(g) + 6H2O(1)
Calculate the enthalpy change for this reaction given the following enthalpies of formation:
A;H / kJ mol C5H12(1) = -147 CO2(g) = –394 H20(1) = -286
Transcribed Image Text:Pentane is a good fuel that burns well in oxygen. C;H12(1) + 802(g) → 5CO2(g) + 6H2O(1) Calculate the enthalpy change for this reaction given the following enthalpies of formation: A;H / kJ mol C5H12(1) = -147 CO2(g) = –394 H20(1) = -286
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