▾ Part A For the reaction Ke=82.8 at a temperature of 169 °C. Calculate the value of K Express your answer numerically. ▸ View Available Hint(s) K₂ 5.07 107 Submit Previous Answers VO AXp Part B X Incorrect; Try Again; 5 attempts remaining For the reaction Kp1.06x10-2 at a temperature of 151 °C. Calculate the value of K. Express your answer numerically. ▸ View Available Hint(s) K₂= Submit ? ΠΟΙΑΣΦ ? 3A(g) + 3B(g) = C(g) X(g) + 2Y(g) 3Z(g)

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 56QRT
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Part A
For the reaction
Kc = 82.8 at a temperature of 169 °C.
Calculate the value of Kp.
Express your answer numerically.
▸ View Available Hint(s)
Kp 5.07.10
Submit
Part B
IVD ΑΣΦ
|
X Incorrect; Try Again; 5 attempts remaining
Previous Answers
For the reaction
K₂ =
Kp = 1.06x10-2 at a temperature of 151 °C.
Calculate the value of Ke.
Express your answer numerically.
► View Available Hint(s)
ΑΣΦ
Submit
?
?
3A(g) + 3B (g) = C(g)
X(g) + 2Y(g) =3Z(g)
Transcribed Image Text:Part A For the reaction Kc = 82.8 at a temperature of 169 °C. Calculate the value of Kp. Express your answer numerically. ▸ View Available Hint(s) Kp 5.07.10 Submit Part B IVD ΑΣΦ | X Incorrect; Try Again; 5 attempts remaining Previous Answers For the reaction K₂ = Kp = 1.06x10-2 at a temperature of 151 °C. Calculate the value of Ke. Express your answer numerically. ► View Available Hint(s) ΑΣΦ Submit ? ? 3A(g) + 3B (g) = C(g) X(g) + 2Y(g) =3Z(g)
The equilibrium constant, K., is calculated using molar concentrations. For gaseous reactions another form of the equilibrium constant, Kp, is
calculated from partial pressures instead of concentrations. These two equilibrium constants are related by the equation
K₂ = K. (RT)An
where R = 0.08206 L-atm/(K-mol), T is the absolute temperature, and An is the change in the number of moles of gas (sum moles
products - sum moles reactants). For example, consider the reaction
N₂(g) + 3H₂(g) = 2NH3(g)
for which An=2-(1+3) = -2.
Transcribed Image Text:The equilibrium constant, K., is calculated using molar concentrations. For gaseous reactions another form of the equilibrium constant, Kp, is calculated from partial pressures instead of concentrations. These two equilibrium constants are related by the equation K₂ = K. (RT)An where R = 0.08206 L-atm/(K-mol), T is the absolute temperature, and An is the change in the number of moles of gas (sum moles products - sum moles reactants). For example, consider the reaction N₂(g) + 3H₂(g) = 2NH3(g) for which An=2-(1+3) = -2.
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