ow development for the solution Find the confidence level for the following critical values (using the Z table): c) z = 2.58 d) z = 2.76
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Show development for the solution
Find the confidence level for the following critical values (using the Z table):
c) z = 2.58
d) z = 2.76
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- The following are two computed confidence intervals for a population mean: (100.01, 110.05) (100.05, 110.10). One interval has a confidence level of 95% and the other interval has a confidence level of 99%. Which interval has the 95% confidence level and which has the 99% confidence level? (Hint: Find the width of each interval and note that the larger width has the larger confidence. This problem does not require Excel) (100.01, 110.05) is the 95% interval, (100.05,110.10) is the 99% O (100.01, 110.05) is the 99% interval, (100.05,110.10) is the 95%High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers have calculated the maximum horsepower for the engine to be 800 HP. Twenty five engines are randomly selected for horsepower testing. The sample has an average maximum HP of 870 with a standard deviation of 80 HP. Assume the population is normally distributed. Step 1 of 2: Calculate a confidence interval for the average maximum HP for the experimental engine. Use a significance level of a = 0.01. Round your answers to two decimal places.Use a t table to find the value of t to use in a confidence interval?
- Given are five observations for two variables, X and Y. Develop the 90% confidence and prediction intervals when x = 6.Using the data provided 1. find the confidence interval 2. find the error boundB. Find the length of the confidence interval given the following data: 6. s = 5.36, n = 350, confidence level: 99% %3D 7. s = 2.35, n = 250, confidence level: 99% 8. s = 1.20, n = 200, confidence level: 95% %3D 9. s = 8.15, n = 29, confidence interval: 99% %3D 10. s = 3.25, n = 17, confidence interval: 95% C. Solve the following problems. 11. In a group presentation, the average geometric reasoning of Grade 10 students in a Mathematics camp was observed to be 80 with s standard deviation of 4. A researcher wants to replicate the study to estimate the true population mean u to within 0.5 maximum error. If the 98% level of confidence is adopted, how many respondents are needed? 12. Teacher Carol, wants to conduct a survey about the average number of students in a certain school who wants online class instead of distance modular learning. If she plans to use 99% confidence level, 0.5 as the margin of error, and a standard deviation of 5. How many sample sizes does she need for the…
- What is the value of Z for this confidence interval?you used the percentage of alcohol to predict wine quality. The data are stored in Vinho Verde. For these data, SYX = 0.9369 and ℎi= 0.024934 when X = 10. a. Construct a 95% confidence interval estimate of the mean wine quality rating for all wines that have 10% alcohol. b. Construct a 95% prediction interval of the wine quality rating of an individual wine that has 10% alcohol. c. Explain the difference in the results in (a) and (b).5. Find the ta values for the following situations: (a) n = 101 93% confidence = 21, confidence = 91% = 101, confidence = 82% (b) n = (c) n ple azy brsg (d) D.F. 70 confidence = 98% (e) D.F. = 17 confidence = 77%
- I need the 95% confidence interval for part a and for part b it would be set up as Ho: mew = 3.1 H1: mew > 3.1let the variable T stand for a student t-distributed variable. find the following a. in a sample of 20 students, the t-value to use to determine a 95% confidence interval for a mean b. in a sample of 30 students, the t-value to use to determine a 98% confidence interval for a meanII. A. Find the t-value corresponding to each level of confidence and degrees of freedom. 1. 90% confidence level and n= 12 2. 99% confidence level and n=20 3. a = 5% and n= 16 A