On the soil profile shown, how high should the GWT rise/fall so that the effective stress at C is 111.1 kN/m³. Assume Ysat,clay to be the same for both layers. Given:
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- For the soil profile shown in Figure 3. Find the value of the vertical stress change at point A. when the water level increases from level b-b to level c-c. fig. (3) REY Sand 84:18-14 KN/² _W_C% = 11.0% XK 3-0m *c sat=21-35 16/17 sand b. clay 18544-20-35-3.0m A Rock 3.0m b2 Refer to the soil profile shown in figure below CALCULATE TOTAL STRESS (ot) AT POINT B put of G.W.T Sand 5m Y sat = 20. 9 Clay 4m Ysat = 17. 8 Let the point A at depth "0", point B at depth "Sm". and point C at depth 9m Select one: Select one: O a. 102.3 KN/M2 Ob. 107 KN/M2 O c. 109 KN/M2 O d. 104.5 KN/M2 Next page evious pagesurface layer QY A Soil profile consists of a surface of Line sand 6m thick with unit weight of 16-5 kN/m³ and clay layer of 8m thick beneth the Sand layer. the water table is located at adepth of 4m below the ground surface: submergend for line Sand is 10.4 kN/m², Gs love clay layer is 2.7 & wc %. = 30% Calculate the eflective stress at the middle of clay Layer. + 6m 4M DW.T Fine Sand 8m clay 8=165& M2 sub = 1o.y tw G3=2=7 w;. = 30%.
- the results of a consolidated undrained test, in which o3 = 392 kN/m?, %3D on a normally consolidated clay are given next: Axial Strain, % Ao, kN/m2 Ud, kN/m? 0.5 156 99 0.75 196 120 1 226 132 1.3 235 147 2 250 161 3 245 170 4 240 173 4.5 235 175 Draw the kf line in a p' vs q' diagram. Also draw the stress path for the test in the diagram.Calculate the vertical stress at 20 ft depth, given the concentrated load 250 tons, Poisson's ratio 0.45 (stiff to soft clays 0.20 -0.45), and the horizontal distance from the point of application of point P at which p is desired 16 ft. Consider = 3.14 KYKY 0.68 01.08. 1.25 0.14 O 0.04 P= 250 tons r = 16 ft TIKXKX 2= 20 ft5-4 For the given soil profile and the piezometric surfaces measured at the top of the two sand and gravel layers, determine the pore pressure and effective stress at points A, B, C, D, and E. Piezometers 2 m Ground surface 2 m Sand y = 18 kN/m3 Water table y_ 11m Y = 20 kN/m3 A 4 m Clay Y = 18 kN/m3 加。B 1Im 5 m Sand and gravel y = 22 kN/m3 2 m •D 5 m Clay Y = 19 kN/m3 Sand and gravel y = 23 kN/m3 %3D Cpyright by
- 18 Refer to the soil profile shown. Given H1 = 9.80 m., and H2 = 5.17 m. If the ground water table rises by 2.39 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer. Properties of dry sand: Gs = 2.58, e = 0.68. Properties of clay: Gs = 2.72, e = 0.81. Round off to two decimal places.Dry Sand H, Groundwater Table Clay Refer to the soil profile shown. Given H1 = 8.85 m., and H2 4.01 m If the ground water table rises by 2.19 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer Properties of dry sand Gs = 2.51, e = 0.65 Properties of clay. Gs = 2.72, e = 0.84. Round off to two decimal places. Activate Windows Go to Settings to activate Windows. < Question 18 of 20 2 A Moving to another question will save this response. ASUS C8O CD 80 5n E R- T Y H]Plot the variation in the effective stress (o') for the given soil profile. Plot your answer here below. Gs = 2.65 e = 0.50 Gs = 2.65. 1.80 m 0.90 m Zone of Capiary Rise Gs= 2.65, e= 0.5 S= 45% Free Surface o = 42 % 1.80 m Gs = 2.71
- 0.4. For thesown soil profile, determine the vertical total and effective stress at points a, b Clay y = 18 N m3 Ysat = 19.5 EN m 4 m and c. Sand, sat = 17 AN m? Sand, Gs =2.65, e 0.8 5 mconsolidated drained triaxial test was conducted on a granular soil. At failure (σ1^')/(σ3^' ) = 4.0. The effective minor principal stress at failure was 100 kN/m2. Compute angle of friction^' in degrees. a. 39 b. 41 c. 37 d. 35تحرير The total volume of a soil specimen is 80,000 mm3 and it weighs 150 grams. The dry weight of the specimen is 130 grams and the density of the soil solids is 2680 Kg/m3. Find the WATER CONTENT IF SATURATION =100% knowing that pwater=1000kg/m3 Select one: O a. 24.2% Ob. 12.2% c. 17.2% d. 16.2%