On a railroad line, two tangents that intersect at station 10+243 so as to form an angle of 36028' are to be connected by a compound curve consisting of two simple curves. The BC which is at station 10 + 163 is to be a 40 curve based on a 20 m chord and is to have a central angle of 170. Compute R2, the stationing of PCC, and the length of tangent from Pl to EC. 10 + 243 PI 36°28' v1 t1 t2 V2 PCC EC 10 + 163 BC R2 R1

On a railroad line, two tangents that intersect at station 10+243 so as to form an angle of 36028' are to be connected by a compound curve consisting of two simple curves. The BC which is at station 10 + 163 is to be a 40 curve based on a 20 m chord and is to have a central angle of 170. Compute R2, the stationing of PCC, and the length of tangent from Pl to EC. 10 + 243 PI 36°28' v1 t1 t2 V2 PCC EC 10 + 163 BC R2 R1

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: What is the length of a vertical parabolic curve in meter if you know (g1=+2.5%, g2=-1.5%) and…

A: Given data: g1=+2.5%g2=-1.5%P.V.C=24.669P.V.I=27.941P.V.T=21.132

Q: A compound curve has the following data: I1 = 28°, I2 = 31°, D1 = 3°, D2 = 4°; Find the stationing…

Q: On a railroad line, two tangents that intersect at station 10 + 243 so as to form an angle of 36°28′…

A: D1 = 4°, bateat of 20 m chanal for 20 m chanal p' = 1146R1 4° = 1146R1…

Q: Situation6: For the next four items, the back tangent and the forward tangent of a parabolic curve…

A: Given values: Back tangent grade = +2.5% Forward tangent grade = -5% Point of Intersection, PI = STA…

Q: From a known point V (vertex), the tangent lines of a compound curve are drawn - having azimuths…

A: *Multiple questions* As per our guidelines we are supposed to answer?️ only one question. Kindly…

Q: A parabolic curve having a forward tangent of -3% intersects a back tangent of 6.5% at sta 10=800…

Q: The common tangent CD of a reversed curve is 280.50 m. and as an azimuth of312°29’. BC is tangent of…

Q: Simple Curves: A highway curve was designed to connect intersecting tangents at Pl. Back tangent = N…

Q: SITUATION 17: AB and BC are tangents of a simple curve. AB is due north and BC is N50°E. Degree of…

A: From the Above ∆of the curve = 50° Degree of the curve = 4 ° For 20 m chain Degree D = 1146/R R=…

Q: D A horizontal curve with P.C. is stationed at 3+025.42 and having a radius of 120m. A property line…

Q: Determine the exact slope of the tangent line to the polar curve r = 02 at the point where 0 = T/2.

Q: A line connecting the point of curvature and point of tangency of 2 simple curves is 280 meters.…

A: Given:- A line connecting the P.C. and P.T of two simple curves = 280 m The angle made between line…

Q: A compound circular curve has: R₁ = 500m, R₂ = 750m, A₁ = 38° 20', A2 = 41° 30′ St. P.I = (28+50)…

Q: The length of common tangent of a compound horizontal curve is 520 m. D₁ = 3°, I₁ = 50°, I₂ = 35°.…

A: Error in horizontal angle=(50°0'0"-0°4'0")-(30°0'0"-0°4'0")=49°56'0"-29°56'0"=20°

Q: the three courses AB, BC and CD have bearing N56°30'E, N80°30'E and S32°17'E, respectively. if BC=…

A: Given Data: AB=N56°30'EBC=N80°30'ECD=S32°17'E

Q: Two tangents that cross at station 10 + 243 to produce an angle of 36°28' must be linked on a…

Q: The length of the common tangent of a compound curve is 321 m. D1 = 2.5°, I1 = 36°, 12 = 62°. Find…

Q: Provide illustration and complete solution. The azimuth from North of lines AB and BC are 330° and…

Q: SITUATION 2: Given a compound curve with li = 18°, l2 = 23.5°, Di = 2° and D2 = 4°. 5. Determine the…

Q: Two tangents intersect at station 26+050. A compound curve laid on their tangents has the following…

Q: 1. In a compound curve, the line connecting the PI at point V and the PCC is an angle bisector. AV…

A: Schematic diagram of the given problem:

Q: The PVI of a vertical summit parabolic curve is located at Sta. 14+750 with elevation of 76.30m. The…

Q: From a known point V (vertex), the tangent lines of a compound curve are drawn - having azimuths…

Q: A vertical sag parabolic curve has a length of 450m. Its back tangent has a slope of -3.20%. The…

Q: From a known point V (vertex), the tangent lines of a compound curve are drawn - having azimuths…

Q: From a known point V (vertex), the tangent lines of a compound curve are drawn having azimuths 300°…

Q: A 7.15° horizontal curve has a central angle of 36.7°. If the station of PT is at 25+198, determine…

Q: 26.9 A vertical parabolic curve has a back tangent of -5% and a forward tangent of +3%. If the…

A: Note:- Hi! Thank you for the question As per the honor code, We’ll answer the first question since…

Q: A railroad curve runs a 6º curve to the PCC, 300m long from the PC of the Compound Curve, thence…

Q: nects two tangents AB and BC with bearings N 85 deg 30 min E and S 68 deg 30 min E respectively. If…

A: Given:- AB and BC with bearings N 85 deg 30 min E and S 68 deg 30 min E stationing of the Vertex is…

Q: The symmetrical parabolic curve passes through point A whose elevation is 23.23m at a distance of…

A: The given values are as follows,The point A elevation=23.23mFrom A curve the distance =54mThe…

Q: 24.14 Railroad curve with T 300.00 ft, D. 230', and PI station 48+ 00.00 24.13 Highway curve with T=…

A: Dc=2o30'' T=300 ft, PI=48+00.00R=5729.6Dc=527362.5=2291.84 ftR=2291.84 ftTangent…

Q: Calculate the chainage of the tangent points of the compound curve from the following: R2=480m.…

Q: 3- A 60 curve has forward and back tangents thst intersect at station 14+87.33

A: Given: The degree of curve is 6°. The point of intersection is 14+87.33. And, I=11°21'35''

Q: H.w-Curves.p... > Calculate the chainage of the tangent points of the compound curve from the…

Q: The azimuths of the back and forward tangents (measured from North) of a simpl curve respectively…

Q: 5. A simple curve has a radius of 272.6m. Its distance from PC to PT along the curve is 256m.

A: CALCULATIONS FOR SIMPLE CIRCULAR CURVE

Q: 2. The tangent lines of a simple curve have azimuths 300° and bearing N 04° E, respectively. A third…

Q: 1. From a known point V (vertex), the tangent lines of a compound curve are drawn - having azimuths…

A: Given Compound curve with azimuth of back, common & forward tangent To Determine a. Radius of…

Q: A circular highway curve has the following design elements: • 1 = 65°32'17" • D= 3°52'00" • Pl…

A: Question is based on the circular highway curve . Latitude ,departure and station of PI are given in…

Q: A reversed curve is connecting the two tangent lines AB and CD having directions of due East and S…

A: given data,radius of first curve=200mradius of second curve=400mIED =300m long…

Q: A simple curve has an external distance of 11.54m and a middle ordinate of 11.10m. The tangents…

Q: A symmetrical parabolic curve passes through point A whose elevation is 23.23m at a distance of 54…

Q: given a compound curve with I1=18' , I2=23.5' , D1=2' and D2=4' determine: a. The length of cord…

A: GIVEN I1=18° , I2=23.5° , D1=2° and D2=4° stationing of PI = 14+120. To Determine a. The length of…

Q: SITUATION 12: AB and BC are tangents of a simple curve. AB is due north and BC is N50°E. Degree of…

Q: A parabolic curve having a forward tangent of -3% intersects a back tangent of +6.5% at station 10 +…

A: Given Data:g1=-3%g2=+6.5%station=10+800elevation= 250.60mL=400m

Q: 1. From a known point V (vertex), the tangent lines of a compound curve are drawn - having azimuths…

Q: Two tangents intersect at station 26+050. A compound curve laid on their tangents has the following…

A: A compound curve is generally two or more than two simple curves that generally has various centers,…

Q: Two tangents intersecting at V has an angle of intersection of 30 degrees. Two points A and B are…

A: Tangent Length can be calculated by finding the central angle of the curve, in degrees. This angle…

Q: 2. The tangent lines of a simple curve have azimuths 300° and bearing N 04° E, respectively. A third…

Concept explainers

Instruments for Surveying

Surveying is the practice that determines the relative three-dimensional positions of many different points on the earth’s surface. There are various instruments used in Surveying like Theodolites, Total station, Tripod stands, Plane table, etc. for measuring horizontal angle, vertical and sloping angle, which are very useful for giving accurate and precise measurement.

Question

On a railroad line, two tangents that intersect at station 10+243 so as to form an angle of 36028' are
to be connected by a compound curve consisting of two simple curves. The BC which is at station
10 + 163 is to be a 40 curve based on a 20 m chord and is to have a central angle of 170. Compute
R2, the stationing of PCC, and the length of tangent from Pl to EC.
10 + 243
PI
36°28'
V1.
ti
t2
V2
PCC
EC
10 + 163
BC
R2
R1

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step 5

Step 6

Answer:

Trending now

This is a popular solution!

Step by step

Solved in 7 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Simple Curve A railway curve is to connect intersecting tangents with the following design data: Back tangent = N 20° 25' E Forward tangent = S 49°35' E Degree of curve = 5⁰ Design speed = 70 Kph Station PI = 5+555.55 1.Determine the length of line from PC to Pl. a) 234.67m b) 244.67m 2.Compute the straight distance from PC to PT. a) 402.34m b) 375.60m c) 245.89m d) 327.42m c) 389.78m d) 423.67m 3. If the width of the land intended for the railway is 10m, determine the area of land from PC to PT. a) 4,456.56 sqm b) 3,456,43 sqm c) 5,112.34 sqm d) 4,399.92 sqm 4.How long would a 300m long train able to leave the curve completely. a) 25.67 sec b) 38.06m sec c) 40.34 sec d) 29.67 sec
Two lines XV and YV intersect at an inaccessible point V. Two points A and B are selected on lines XV and YV respectively. Length of AB = 180 m, angle XAB =110°, and angle ABY = 130°. The two straights are to be joined by a curve of 500 m radius. The stationing of point A is 2+500. Calculate the following: a. distance VA b. distance VB c. tangent lengths d. distance XA e. distance YB f. stationing of beginning of the curve g. length of the curve h. stationing of end of the curve
Two tangents BC and CD intersect at an angle of 34° are to be connected with a simple curve. A point P on the curve is located 22.03m from point C and has a perpendicular distance of 2.89m from line BC. Calculate: a. The radius of the simple curveb. The length of chord connecting P.C. and point P.c. The stationing of P if vertex of the curve is at 10+100m
The intersection of two proposed tangent AB and CD are inaccessible. From point E which is at Sta 10+266 on Tangent AB. The line EF is run to the point F on the Tangent CD The angle between the prolongation of AB and the line EF as measured by the transit is found to be 37 degrees. The line EF is measured and found to be 134.50 m and the angle between EF and the prolongation of CD is 24 degrees. If Tangent AB and CD are to be connected by 5 degrees. Find the Sta PC, Sta PT, and the Distance from PT to F.
In a railroad layout, the centerline of two parallel tracks are connected with a reversed curve of unequal radii. The central angle of the first curve is 16° and the distance between the parallel tracks is 27.6 m. Stationing of the PC is 15 + 420 and the radius of the second curve is 290 m. Compute: a. The length of the long chord from the PC to the PTb. The radius of the first curvec. The stationing of the PT
1. The intersection of two proposed tangent AB and CD are inaccessible. Therefore, from point E which is at Sta 10+266 on Tangent AB. The line EF is run to the point F onn the Tangent CD. The angle between the prolongation of AB and the line EF as measured by the transit is found to be 37 degrees. The line EF is measured and found to be 134.50 m and the angle between EF and the prolongation of CD is 24 degrees. If Tangent AB and CD are to be connected by 5 degrees, Find: a. Sta PC b. Distance from PT to F
Two tangents BC and CD intersect at an angle of 34° are to be connected with a simple curve. A point P on the curve is located 22.03m from point C and has a perpendicular distance of 2.89m from line BC. Calculate: The radius of the simple curve The length of chord connecting P.C. and point P. The stationing of P if vertex of the curve is at 10+100m.
The PI of a highway is located in a lake at point C. Stations A and B are selected to replace the inaccessible PI, which is lying along a line through PC and PT respectively. The stationing of PC is 15+140 while that of A is 15+410. If angle CAB is equal to 22 degrees and line AB is parallel to the chord with a length equal to 380 m. Determine the following: Radius of the curve. • Degree of curve. • Length of curve. • Stationing of PT.
The bearings of forward and backward tangent are N 15°30’ E and N 25°40’ W, respectively. If the degree of curve is 2° for a full station of 20m and the stationing of the vertex is 12 + 582.50, determine the ff with illustrations and sketch : a. Elements of the curveb. Stationing of P.C. and P.T.c. Lengths of sub-chords and its corresponding sub-angles
The bearings of forward and backward tangent are N 15°30’ E and N 25°40’ W, respectively. If the degree of curve is 2° for a full station of 20m and the stationing of the vertex is 12 + 582.50, determine the: a. Elements of the curveb. Stationing of P.C. and P.T.c. Lengths of sub-chords and its corresponding sub-angles
The bearings of forward and backward tangent are N 15°30’ E and N 25°40’ W, respectively. If the degree of curve is 2° for a full station of 20m and the stationing of the vertex is 12 + 582.50, determine the:a. Elements of the curveb. Stationing of P.C. and P.T.c. Lengths of sub-chords and its corresponding sub-angles
Q.NO (03) Two targents AB & BC are intersected by a line KM. The angles AKM and KMC are 130°& 140° respectively. The radius of 1st arc is (I.D-200) mand of 2nd arc is |(1.D-150) m Find the chainage of tangent points and the point of compound curve given that the chairage of intersection point is (I.D-300) m B Ts N K M T1 Re T2 R O2