On a particle of mass m = 20gr, three forces F1, F2 and F3 act in the plane of the paper. The forces F2 = 4N, F3 = 3 N and F1 is unknown as indicated in the figure. If a product
Q: A particle is subjected to the action of two forces : F1 = 41+ 3 + 6 k [ kN ] and F2 = 51-61 -5k […
A:
Q: In the very Dutch sport of Fierljeppen, athletes run up to a long pole and then use it to vault…
A: Let m denote the mass of the vaulter, r denote the distance of the vaulter from the bottom of the…
Q: Use the rectangular component method to solve the fol- lowing problems. Determine the magnitude R of…
A: Unit vector along force F1 is Unit vector along force F2 is The resultant of the two forces is…
Q: The resultant of four coplanar, concurrent forces is 600 lb, directed S 40oE. Three of the forces…
A:
Q: An athlete pulls box E using an inextensible rope P while being resisted by another inextensible…
A:
Q: A body of mass 3.56 kg is moving toward x direction with the velocity V = (a-bt)(c-dt), where t is…
A: V= (a-bt)(c-dt) a= dV/dt = (c-dt)×d(a-bt)/dt + (a-bt)×d(c-dt)/dt => a= (c-dt)×(-b) + (a-bt)×(-d)…
Q: Consider 2 forces acting on a mass of 2.42 kg. F1 = 10.4 N @ 18.1 degrees and F2 = 7.07 N @ 66.4…
A: Given Forces are F1 = 10.4 N @ 18.1 degrees measured relative to the +x direction. and F2 = 7.07 N…
Q: An electron is a subatomic particle (m = 9.11 x 10-31 kg) that is subject to electric forces. An…
A: Given Data: The mass of an electron is, m=9.11 x 10-31 kg The initial velocity of an electron is,…
Q: An athlete pulls box E using an inextensible rope P while being resisted by another inextensible…
A: when the box is moving on the surface and the normal force on the box by the surface is N and the…
Q: There are two forces on the 1.82 kg box in the overhead view of the figure but only one is shown.…
A: There are two forces on the 1.82 kg box in the overhead view of the figure but only one is shown.…
Q: A concurrent force system in space is composed of 3 forces described as follows. P1 has a magnitude…
A: d=x2+y2+z2⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√
Q: y 60 N 45 N 300 25° 52 N 100 200 26 N 75° 30 N
A: F1 = 52 N @ 10o North of east F2 = 45 N @ 30o East of north F3 = 60 N @25o North of west F4 = 26 N…
Q: A particle with a mass of 10 kg is moving at a velocity of (3t^2 + 4t)j m/s. What would be the…
A: Given value--- mass = 10 kg. velocity = (3t^2 + 4t) j. We have to find--- expression of external…
Q: It is desired to replace the 560 N force R acting on particle A with two forces P and Q which will…
A: Horizontal component balance P cos 20°+? cosθ=R cos 50°⇒270 cos 20°+? cosθ=560 cos 50°⇒?…
Q: QI) At point A, the four forces FB, Fe, Fp and Fg act, the lines of action for these forces are…
A:
Q: A particle of mass 3 kg is moving with constant velocity of magnitude 10 m/s for 20s. The magnitude…
A: Mass of the body m=3 kg Velocity of the body v=10 m/s Time for which the body moves with constant…
Q: Consider 2 forces acting on a mass of 2.47 kg. F1 = 11.0 N @ 24.5 degrees and F2 = 7.45 N @ 75.7…
A: Given data: The mass, m=2.47 kg. The magnitude of the first force F1 acting on mass m, F1=11.0 N.…
Q: Determine the magnitude F and direction (measured clockwise from the positive y-axis which is…
A:
Q: The three forces F1 = 0.8 kN, F2 = 0.6 kN and F3 act on particle P as in the sketch. F1 = 0.8 kN F2…
A: GivenF1 = 0.8 KNF2 = 0.6 KNF3 is acting as shown in figurewe have to calculate the magnitude and…
Q: On a particle of mass m = 20gr, three forces F1, F2 and F3 act in the plane of the paper. The forces…
A:
Q: A girl walks 3 m due east and then 4 m due north 1. The girl's displacement from the starting point…
A: Girl walk 3m east then 4m north Net displacement from starting point=?
Q: The magnitude of the resultant of two concurrent forces F1 and F2 with the angle 0 is O VF} + F +…
A:
Q: A particle with a mass of 10 kg is moving at a velocity of (3t^2 + 4t)j m/s. What would be the…
A:
Q: A particle, which remains at rest, is acted on by three forces F, G and H. The force F has…
A:
Q: .Show that the components of the force on m2 due to m1 are: Gm1m2x Fx (x²+y²+z²)7 Gm,mży • Fy 3…
A: Part 1. The magnitude of position r will be: Gravitational potential energy = The gravitational…
Q: A force acts at the origin of a coordinate system in a direction defined by the angles θx = 69.3°…
A: Given: The angle from the x-direction is 69.3°. The angle from the z-direction is 57.9°. The…
Q: A particle, which remains at rest, is acted on by three forces F, G and H. The force F has…
A:
Q: Consider 2 forces acting on a mass of 2.64 kg. F1 = 10.8 N @ 24.8 degrees and F2 = 6.96 N @ 66.1…
A: Given: Mass m = 2.64 kg. Forces are, F1=10.8 N @ 24.8o from x axisF2=6.96 N @ 66.1o from x axis
Q: Two forces, F1 and F2, act on the m = 7.35 kg block shown in the drawing below. The magnitudes of…
A:
Q: It is desired to replace the 560 N force R acting on particle A with two forces P and Q which will…
A: "Since you have asked multiple question, we will solve the first question for you. If you want any…
Q: 8. (: nd the magnitude of the resultant force (the sum of the two vectors) and the angle it makes…
A: Analyze the FBD of the system.
Q: A particle, which remains at rest, is acted on by three forces F, G and H. The force F has magnitude…
A: Required magnitude of G and H forces
Q: Find the magnitude of the resultant of the concurrent force system below y B (15.0 m) D (10.0 m)…
A:
Q: Use the rectangular component method to solve the fol- lowing problems. Determine the magnitude R of…
A: Rectangular component method of vector addition is a method to add number of vectors which are…
Q: Determine the magnitude of the resultant and its direction angle from x, y, and z axis for the…
A: Given: F1 = 465+6 = 471 lbr1=(4,5,3)F2=2060/10 = 206lbr2= (-6,4,-5)F3=300 lbr3=(6,-2,-4)
Q: A baseball with a mass of 0.145 kg is moving horizontally to the right with an initial velocity of…
A: Given: The mass of baseball m = 0.145 kg. Initial velocity of baseball u = 40 m/s. After hitting by…
Q: A force F is applied at the top of the tower at A. If it acts in the direction shown such that one…
A:
Q: m1 m2 F. m3 Three blocks are placed in contact with each other and their masses are m1 = 10.9 kg, m2…
A: We know Newton's second law of motion F=ma
Q: Three 0.300-kg billiard balls are placed on a table at the corners of a right triangle as shown in…
A:
Q: According to a simplified model of a mammalian heart, at each pulse approximately 20 g of blood is…
A:
Q: Determine the resultant of the force system shown in fig. and the angle e which the * ?resultant…
A: here we need to find the angle
Q: Given through the indicated points: A=280kN (12, 6, -4); B=520KN (-3, -4, 12); and C=270KN…
A: We need to find the resultant force of the system of forces given in the question. Also it is…
Q: The following forces are acting on a particle: 500 N due east; 300 N 30o E of S; Z Newton 60o West…
A: The magnitudes of forces F1, F2, F3, and F4 are given as follows.
Q: A particle, which remains at rest, is acted on by three forces: F, G & H. The force F has a…
A:
Q: As shown in the figure below, two objects are moving towards each other with velocities given by the…
A: The velocities V2 and V3 in vector form will be: And, Assume that the magnitude of the velocity V1…
Q: In the plane forces system, F1 = 3 kN, F2 = 6 kN and F3 = 10 kN. The direction of the force F3 is…
A: Given, F1=3k Newton F2=6kN F3=10kN Tanα=3/4 d1=2m
Q: An athlete pulls box E using an inextensible rope P while being resisted by another inextensible…
A:
Q: Two blocks with masses M| and M2 are connected by a massless string that passes over a massless…
A: M1= 2.25 kg , u1= 0.205 ,42.5° M2= 7.35 kg, u2= 0.105 ,34.5°
Q: A person of mass m= 80 kg pushes a fridge of mass M = 140 kg across a floor with a constant velocity…
A: Mass of the person = m = 80 kg Mass of the fridge = M = 140 kg Here the fridge is moving with…
On a particle of mass m = 20gr, three forces F1, F2 and F3 act in the plane of the paper. The forces F2 = 4N, F3 = 3 N and F1 is unknown as indicated in the figure. If a product of the action of these three forces the particle acquires an acceleration a = 0.2m/s2 in the direction θ=20°, determine the direction and the magnitude of the force F1.
- The alpha angle of the direction of the force F3 is 300°
Step by step
Solved in 3 steps with 2 images
- Three force vectors act on a free body at the origin as shown. F1= 4 N F2=2.0 i + 3.1 J N F3= 6.3 N at 35° relative to positive x axis. a) Report the unit vector in the direction of F3 (in unit vector or i,j,k notation to 4 sig figs) b)Calculate the resultant force R, which is the sum of the three forces F1,F2, and F3 (in unit vector or i,j,k notation to 4 sig figs)Determine the magnitude of the y-component of force Q (N) if P=108.8 N, Q = 72.5 N , θ= 42.25° and α = 43.45°. Round off only on the final answer expressed in 3 decimal places. Instead of units, indicate the direction of the y-component.A two dimensional force system is given. The objective is to find the resultant force of the system by using vector operations. There are three forces present in the system. A. Find the vector form for each of the three forces: F1=10, Theta 1=45: F2=40x Theta 2=135; F3=30, Theta 3=270 B.Find the vector form of the resultant force C.Find the magnitude of the resultant force D. Find the angle of the force referred from the x-axis and describe its direction
- The slope of the 7.9 kN force F is specified as shown in the figure. Express F as a vector in terms of the unit vectors i and j. Assume a = 11, b = 5. Answer: F = (i a b -x i+ MI j) kNGiven the force F2 and the u and v axes. What are the magnitude (in Newton) of the component of this force along the u and v axes respectively.In the plane forces system, F1 = 3 kN, F2 = 6 kN and F3 = 10 kN. The direction of the force F3 is tan a = %, the moment arm of the force couple is di = 2 m and the action points of the forces are A2 (-2,5), A3 (-4,-4). Find the resultant force R as a vector and calculate the line of action. y F2 A2 H. F3 A3
- F = (-30i + 60j + 60k )kN %3D Forces are concurrent at point O. Determine the magnitude of the resultant of the three vectors. a 71.5 kN b 187 kN F, = (60i – 20j+ 15k )kN c 116 kN d 83.7 kN Determine the angle between F, andF,. F, = (20j – 25k)kN X а 111° b 132° c 69.0° d 21.0° Select the expression that denotes a unit vector in the direction and sense of F,. a 0.625j -0.781k b 0.625i -0.781j c -0.625 j –0.781k d 0.625i +0.781jA block of mass m = 3.65 kg is pushed a distance d = 7.95 m along a frictionless horizontal table by a constant applied force of magnitude F = 16.0 N directed at an angle 0 = 39.0° below the horizontal as shown in the figure below. A block labeled m is on a horizontal surface. An arrow labeled vector F points downward and to the right at an angle e above the horizontal, and acts upon the upper left corner of the block. A faded image of the block is a distance d to the right of the block. (a) Determine the work done on the block by the applied force. (b) Determine the work done on the block by the normal force exerted by the table. (c) Determine the work done on the block by the force of gravity. (d) Determine the work done by the net force on the block.A chandelier hangs h = 0.74 m down from two chains of equal length. The chains are separated from one another by a length L = 0.85 m at the ceiling. The chandelier has a mass of m = 28 kg. What is the angle, θ in degrees, between one of the chains and the vertical where it contacts the chandelier?
- A block of mass m = 2.50 kg is pushed d = 3.00 m along a frictionless horizontal table by a constant applied force of magnitude F = 18.0 N directed at an angle θ = 25.0° below the horizontal as shown in the figure below. A block labeled m is on a horizontal surface. An arrow labeled vector F points downward and to the right at an angle θ above the horizontal, and acts upon the upper left corner of the block. A faded image of the block is a distance d to the right of the block. (a) Determine the work done by the applied force. (b) Determine the work done by the normal force exerted by the table. (c) Determine the work done by the force of gravity. (d) Determine the work done by the net force on the block.A block of mass m = 2.50 kg is pushed d = 2.90 m along a frictionless horizontal table by a constant applied force of magnitude F = 15.0 N directed at an angle θ = 25.0° below the horizontal as shown in the figure below. A block labeled m is on a horizontal surface. An arrow labeled vector F points downward and to the right at an angle θ above the horizontal, and acts upon the upper left corner of the block. A faded image of the block is a distance d to the right of the block. (a) Determine the work done by the applied force. J(b) Determine the work done by the normal force exerted by the table. J(c) Determine the work done by the force of gravity. J(d) Determine the work done by the net force on the block. Jment Chapter 05, Problem 007 There are two forces on the 1.82 kg box in the overhead view of the figure but only one is shown. For F, = 20.0 N, a = 13.5 m/s², and 0 = 21.5°, find the second force (a) in unit-vector notation and as (b) a magnitude and (c) a direction. (State the direction as a negative angle measured from the +x direction.) (a) Number i + jUnits (b) Number Units (c) Number Units Click if you would like to Show Work for this question: Open Show Work SUBMIT ANSWER SAVE FOR LATER Question Attempts: 0 of 10 used