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- Following is a retrosynthetic analysis for the synthesis of the herbicide (S)-Metolachlor from 2-ethyl-6-methylaniline, chloroacetic acid, acetone, and methanol. CI OMe OMe OMe 'N' HN N CI. + НО, Chloroacetic acid (S)-Metolachlor 3 NH2 CI + MEOH OMe Acetone Methanol 2-Ethyl-6-methylaniline Show reagents and experimental conditions for the synthesis of Metolachlor from these four organic starting materials. Your synthesis will most likely give a racemic mixture. The chiral catalyst used by Novartis for reduction in Step 2 gives 80% enantiomeric excess of the S enantiomer.Why is a strong acid (like HCI) used in a Grignard reaction? O 1) A strong acid is used in the Grignar reaction in order to protonate the carbonyl in order to make a better leaving group, OH. Once teh OH leaves, the alcohol group is reformed due to water. A stable tetrahedral intermediate with a negatively charged oxygen forms O 2) that does not possess a leaving group. This intermediate will exist until a proton source from the strong acid protonates the negatively charged oxygen, affording the neutral alcohol product. 3) The use of a strong acid is not necessary. It is simply recommended as it increases the yield produced in the reaction. 4) The use of a strong acid is necessary for the formation of a Grignard reagent. Without a strong acid, the organomagnesium compound cannot be formed.Draw a diagram similar to that in figure 6 detailing the separation of 1,2-dichlorobenzene, phenol (pka = 10), and pyridine by an extraction protocol. OH aa CI 1,2-dichlorobenzene phenol ·N·. pyridine
- IF esize this compound by the → t-butyl ethyl ether Show the steps necessary to synthesize this compound by a rignard reaction. Start with an alkyl halide; after that you can add any organic or inorganic compound. → 1-hexanol Consider the following compounds:Which sequence of steps will give the highest yield of a carboxylic ester product? Mix 0.1 mole of benzoic acid (C6H5CO2H) with 1.0 mol SOC12, remove unreacted SOC12, then add 0.1 mole of isopropyl alcohol O Mix 0.1 mole of benzoic acid (C6H5CO2H) with 0.1 mol of NaOH, then add 1.0 mol of isopropyl alcohol and heat, Men remove any unreacted isopropyl alcohol O Mix 0.1 mole of benzoic acid (C6H5CO2H) with 0.1 mol of NaOH, then add 0.1 mol of isopropyl alcohol and heat Mix 0.1 mole of methyl benzoate (C6H5-(C=0)-OCH3) with 0.1 mol of isopropyl alcohol and stir overnightBecause phenol (C6H5OH) is less acidic than a carboxylic acid, it can be deprotonated by NaOH but not by the weaker base NaHCO3. Using this information, write out an extraction sequence that can be used to separate C6H5OH, benzoic acid, and cyclohexanol. Show what compound is present in each layer at each stage of the process, and if it is present in its neutral or ionic form.
- 11) For the following reaction, identify the Lewis acid and the Lewis base and draw the curved arrow mechanism. H H -N - +) NH2 lewis base lewis Aciol SHN pinb!7 (P 12) Which of the following solvents can be used with NaNH2 and why? 02H (2 (9 HOʻHO H A.A chemist wanted to synthesize the anesthetic 2-ethoxy-2-methylpropane. He used ethoxide ion and 2-chloro-2-methylpropane for his synthesis and ended up with no ether. What was the product of his synthesis? What reagents should he have used?نقطتان )2 Choose the best solvent to the following (Chloroacetic acid) CICH2-C-OH Soluble in ether Not soluble in ether هذا السؤال مطلوب إرسال LAllaa Google lai e 19all 65 Jhl pe beul.okE Google Je lael d9 sall Lia sLail a pl ell la allla ala Google alai
- The reaction between propanoic acid and benzyl alcohol in an acidic medium. Show the product by writing the reaction together with its mechanism.Starting with ethene give a suitable reaction scheme to convert it into Ethyl ethanoate in 4 stepsO NaBH4 Synthesis #2: Select a different set of two substrates and one reagent that could be combined to prepare benzphetamine. tymen Ph Ph Ph Ph NH Ph H O NaBH3CN, H+ 20= ano [H*], NaBH-CN Nucleophile
