nstruction: I already have the answer in this problem but I can't understand some part of it. Look at the image posted to see what part I can't understand and please explain it. I can't understand "Part B". How did he came up with the formula, h3=e2h2?   Topic: Impulse and Momentum A ball is dropped onto a horizontal floor. It reaches a height of 144 cm on the first bounce, and 81 cm on the second bounce. Find (a) the coefficient of restitution between the ball and floor and (b) the height it attains on the third bounce.

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Instruction: I already have the answer in this problem but I can't understand some part of it. Look at the image posted to see what part I can't understand and please explain it. I can't understand "Part B". How did he came up with the formula, h3=e2h2?

 

Topic: Impulse and Momentum

A ball is dropped onto a horizontal floor. It reaches a height of 144 cm on the first bounce, and 81 cm on the second bounce. Find (a) the coefficient of restitution between the ball and floor and (b) the height it attains on the third bounce.

 

 

at top mogt ĥerght 8peed af ball will be
Rence
as per equation ap motion'
Tero',
0? = u? - 29 he
o? = (ev)"- 29 ĥy
e'v?
%3D
S:: 8peed bèfor
IAt impact ;
V= Jzgh
|(formula)
he =
8 imilardy
e?R formula)
%3D
we
Cm write
e? h
0-081 = e? x o-144
e = 0.75) Ans
Part b
height
attained in third bonce
(o-75)" x0•08 1
2
こ
hg= 0-0456m) Ang
Transcribed Image Text:at top mogt ĥerght 8peed af ball will be Rence as per equation ap motion' Tero', 0? = u? - 29 he o? = (ev)"- 29 ĥy e'v? %3D S:: 8peed bèfor IAt impact ; V= Jzgh |(formula) he = 8 imilardy e?R formula) %3D we Cm write e? h 0-081 = e? x o-144 e = 0.75) Ans Part b height attained in third bonce (o-75)" x0•08 1 2 こ hg= 0-0456m) Ang
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