[Ni²+] = Ni²+ (1.20 M) + Cd(s) → Ni(s) + Cd²+ (0.00663 M) AG 42.4 kJ The free energy change for the following reaction at 25 °C, when = 1.20 M and What is the cell potential for the reaction as written under these conditions? Ecell = Would this reaction be spontaneous in the forward or the reverse direction? O forward direction O reverse direction V [ca²+] = = 0.00663 M, is -42.4 kJ:

Chemistry: Principles and Practice
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Chapter18: Electrochemistry
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Problem 18.44QE: For each of the reactions, calculate E from the table of standard potentials, and state whether the...
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The free energy change for the following reaction at 25 °C, when [Ni²+] = 1.20 M and
Ni²+ (1.20 M) + Cd(s) → Ni(s) + Cd²+ (0.00663 M) AG = -42.4 kJ
What is the cell potential for the reaction as written under these conditions?
Ecell
=
V
[Ca²+]
Would this reaction be spontaneous in the forward or the reverse direction?
forward direction
reverse direction
=
0.00663 M, is -42.4 kJ:
Transcribed Image Text:The free energy change for the following reaction at 25 °C, when [Ni²+] = 1.20 M and Ni²+ (1.20 M) + Cd(s) → Ni(s) + Cd²+ (0.00663 M) AG = -42.4 kJ What is the cell potential for the reaction as written under these conditions? Ecell = V [Ca²+] Would this reaction be spontaneous in the forward or the reverse direction? forward direction reverse direction = 0.00663 M, is -42.4 kJ:
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