NH4Cl + CaSO4 → (NH4)2SO4 + CaCl2 Δ Hf NH4Cl = -311.730 Δ Hf CaSO4 = -1434.5 kJ/mol Δ Hf (NH4)2SO4 = -1180,9 kJ/mol Δ Hf CaCl2 = -795.4 kJ/mol What us What is the ΔH°f of the the reactant? What us What is the ΔH°f of the the product? What is the ΔH°rxn of this given reaction? Round your answers in 2 decimal places no need to write the unit
NH4Cl + CaSO4 → (NH4)2SO4 + CaCl2 Δ Hf NH4Cl = -311.730 Δ Hf CaSO4 = -1434.5 kJ/mol Δ Hf (NH4)2SO4 = -1180,9 kJ/mol Δ Hf CaCl2 = -795.4 kJ/mol What us What is the ΔH°f of the the reactant? What us What is the ΔH°f of the the product? What is the ΔH°rxn of this given reaction? Round your answers in 2 decimal places no need to write the unit
General Chemistry - Standalone book (MindTap Course List)
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NH4Cl + CaSO4 → (NH4)2SO4 + CaCl2
Δ Hf NH4Cl = -311.730
Δ Hf CaSO4 = -1434.5 kJ/mol
Δ Hf (NH4)2SO4 = -1180,9 kJ/mol
Δ Hf CaCl2 = -795.4 kJ/mol
What us What is the ΔH°f of the the reactant?
What us What is the ΔH°f of the the product?
What is the ΔH°rxn of this given reaction?
Round your answers in 2 decimal places no need to write the unit
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