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NaOH (aq) +KHC8H4O4 =aq)NaKC8H4O4 (aq) + H2O (l) balnce
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- What is the conjugate acid of H2C6H7O5 -1aq2? What is its conjugate base?HSO4-(aq) + H2O(l) ⟷⟷ H2SO4(aq) + OH-(aq)Phenylamine is an aromatic amine that is used in the manufacture of dyes. When absorbed through the skin itcauses the Fe+2 in hemoglobin to become oxidized into Fe+3, resulting in the formation of methemoglobin whichcannot bind to or transport oxygen. Phenylamine is soluble in water and acts as a weak base.C6H5NH2 (aq) + H2O (ℓ) ⇋ C6H5NH3+ (aq) + OH- (aq)a. When you measure the concentrations of the ionized substances you find them to be:[C6H5NH2] = 0.234 mol/L [C6H5NH3+] = 2.8 x 10-5 mol/L [OH-]= 2.8 x 10-5 mol/LIf the Kb is 4.27 x 10-10, is the reaction at equilibrium? If not, which direction does it need to move (rightor left) to reach equilibrium? Explain. b. At equilibrium the concentrations of the ionized substances are:[C6H5NH2] = 0.0537 mol/L [C6H5NH3+] = 4.79 x 10-6 mol/L [OH-]= 4.79 x 10-6 mol/LIf this reaction is taking place in a 2.0L container, and 1.5 moles of phenylamine were added to thereaction, what will the new concentrations of the three ionic species be when…
- An unknown acid is chosen from the list in the 1223 Lab Procedure. Determine the Identify the unknown diprotic acid. The procedure for identifying an unknown acid is exactly as described in the lab manual. Part 1: Standardization of NaOH. 1.4378 g of oxalic acid was dissolved in 250.0 mL of water and a 25.00 mL aliquote was titrated with NaOH. 24.73 mL of titrant was required. Determine the concentration of sodium hydroxide. Answer: Part 2: Titration of the unknown acid. 1.9875 g of the unknown acid was dissolved in 250.0 ml of water and 25.00 ml of this solution was titrated with the NaOH. 29.50 mL of titrant was required. Determine the Molar Mass of the unknown. on Answer:In the following reaction in aqueous solution, the acid reactant is and its conjugate base is CH;COOH(aq) + H2O * CH3CO0 (aq) + H30 (aq) A CH3COOH; CH3C00 B CH3COOH; NH4 NH3; CH3CO0 D) NH3; NH4" E CH3COOH; H30*What are the products to the reaction depicted below, assuming that CH3CO2H is the acid? CH3CO2H (aq) + H2O (1) = CH3CO2H2*(aq) + -OH (aq)
- Write the conjugate base of C₆H₅NH₂.3. For the following acid - base reaction, (a) predict the products; (b) identify the Bronsted acid, Bronsted base, conjugate acid, and conjugate base; (c) use curved arrows to show the flow of electron pairs in the reaction. CH3 CH2C-OH + NaNHaIn the following reaction in aqueous solution, the base reactant is and its conjugate acid product is CH3COOH(aq) + NH3(aq) CH3COO (ag) + NH4 (ag) O NH3: NH4 NH3: CH3COO CH3COOH; NH4 CH3COOH; H30+ CH3COOH; CH3CO*
- 1) Complete the following reactions and identify the acid, base, conjugate acid and conjugate base. CH;CH,NH2 (aq) + H2O (1) a) CH;COOH (aq) + H,O (I) b) c) Identify the conjugate base and conjugate acid of each of the following. Conjugate Base Molecule Conjugate Acid HCO3 H20 HSO4- H2PO4C5H8O2 + NaH + HCl −→ C5H12O2 + NaClComplete the equation to show how pyridine, C5H5N, acts as a Brønsted-Lowry base in water. equation: C5H5N + H2O