Na AIF, can be made by the reaction below: Al,O3 () + 6 NaOH ) + 12HF → 2 Na AIF +9 H,0 (I) In an experiment; 6.55 g Al,0, and excess HF were dissolved in 1.75 L of 0.15 M NaOH. If 20 g Na AIF was obtained,

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Chapter18: Representative Metals, Metalloids, And Nonmetals
Section: Chapter Questions
Problem 25E: A chemist dissolves a 1.497-g sample of a type of metal (an alloy of Sn, Pb, Sb, and Cu) in nitric...
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Na AIF, can be made by the reaction below:
Al,O3 () + 6 NaOH ) + 12HF → 2 Na AIF +9 H,0 (I)
In an experiment; 6.55 g Al,0, and excess HF were dissolved in 1.75 L of 0.15 M NaOH.
If 20 g Na AIF was obtained,
Transcribed Image Text:Na AIF, can be made by the reaction below: Al,O3 () + 6 NaOH ) + 12HF → 2 Na AIF +9 H,0 (I) In an experiment; 6.55 g Al,0, and excess HF were dissolved in 1.75 L of 0.15 M NaOH. If 20 g Na AIF was obtained,
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