:= n; while I >= 0 do { J : = 1; while J <= n do { } H K := n; while K >= 0 do { Data [I] [J] = Data [K] [J] +Data [K] [I]; K = K-1; } J := J* 3; I = I-2;
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- typedef struct { short data[4];} MatrixElement; void copy_matrix(MatrixElement m1[], MatrixElement m2[], int ROWS, int COLS) { int i, j, k; for (i = 0; i < ROWS; i++) { for (j = 0; j < COLS; j++) { for (k = 0; k < 4; k++) { m1[i*COLS+j].data[k] = m2[i*COLS+j].data[k]; } } }} void copy_matrix_transpose(MatrixElement m1[], MatrixElement m2[], int ROWS, int COLS) { int i, j, k; for (i = 0; i < ROWS; i++) { for (j = 0; j < COLS; j++) { for (k = 0; k < 4; k++) { m1[i*COLS+j].data[k] = m2[j*ROWS+i].data[k]; } } }} You can assume the following conditions: The matrix m1 is allocated at memory address 0, and matrix m2 immediately follows it. Indices i, j, and k are kept in registers. ROWS and COLS are constants. The cache is initially empty before the function call. The cache is write-back (i.e., only writes back to memory when a line is…in c language !! typedef struct {long restaurant_id;char restaurant_name[10];char description[120];double rate;char cuisine[30]; opening_year;long capacity;char city[30];char address[60];char owner[30];} RECORD_t, *RECORD; RECdelete (unsigned long restaurant_id, RECORD *restaurant_array, unsigned long *p_size){int rec;int index;// index <- find the index of the RECORD with given restaurant_id in restaurant_array ????? (I DIDNT)if (index is valid)rec=restaurant_array[index];elserec=NULL;return rec;}int func(int a, int b) { return (ain c language !! typedef struct {long restaurant_id;char restaurant_name[10];char description[120];double rate;char cuisine[30]; opening_year;long capacity;char city[30];char address[60];char owner[30];} RECORD_t, *RECORD; RECORD delete (unsigned long restaurant_id, RECORD *restaurant_array, unsigned long *p_size){int rec;int index;// index <- find the index of the RECORD with given restaurant_id in restaurant_array ????? (I DIDNT)if (index is valid)rec=restaurant_array[index];elserec=NULL;return rec;}Hef sharks_minnows (minnows, sharks): shark_count = 0 minnow_count = len (minnows) for i in range(minnow_count): curr_shark_height = minnows [i] if curr_shark_height is not None: minnows [i] = None for j in range (i + 1, minnow_count): if minnows [j] == curr_shark_height: minnows [j] = None curr_shark_height -- 1 shark_count += 1 return shark_count <= sharks The provided code is imperfect, in that it sometimes returns True when it should return False, and sometimes returns False when it should return True. (a) Provide an example of a function call where the provided code will correctly return True (i.e. a True Positive) (b) Provide an example of a function call where the provided code will correctly return False (i.e. a True Negative) (c) Provide an example of a function call where the provided code will incorrectly return True (i.e. a False Positive) (d) Provide an example of a function call where the provided code will incorrectly return False (i.e. a False Negative)int a[10] = {0,1,2,3,4,5,6,7,8,9};int *m = &a[0];int *p = &a[5];int *q = &a[1]; p = (int) m + (int) p - (int) q; what is the value of of *pvoid fact(int num) { int k,f=1; for (k=1;k<=num; k++) f=f*k; cout<< f; int main() { int arri[3]={3,2,1} ; for(int i=0;i<3;i++) fact(arri[i]); } 261 O 621 O 7 462CFG: Example 1 • Draw the CFG for the following code: int f(int n){ } int m = n* n; if (n < 0) else return 0; return m;Q1 function myFunc() { let a = 10; if (true) { Q3 } } let a = 5; console.log(a); Q4 console.log(a); Q2 const square = num => num * num; console.log(square(3) + 5); myFunc(); let x = 30; let y "200"; console.log(x+y); const nums = [10, 20, 8, 17]; nums.filter(e=> e > 10); console.log(nums); Q5 const nums = [30, 35, 42, 20, 15]; console.log(nums.every (num => num > 20)); January 15Match the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eaxQuery Board Python or Java(Preferred Python please) Thank you! Programming challenge description: There is a board (matrix). Every cell of the board contains one integer, which is 0 initially.The following operations can be applied to the Query Board:SetRow i x: change all values in the cells on row "i" to value "x".SetCol j x: change all values in the cells on column "j" to value "x".QueryRow i: output the sum of values on row "i".QueryCol j: output the sum of values on column "j".The board's dimensions are 256x256."i" and "j" are integers from 0 to 255."x" is an integer from 0 to 31. Input: Your program should read lines from standard input. Each line contains one of the above operations. Output: For each query, output the result of the query. Test 1 Test InputDownload Test 1 Input SetCol 32 20 SetRow 15 7 SetRow 16 31 QueryCol 32 SetCol 2 14 QueryRow 10 Expected OutputDownload Test 1 Input 5118 34if L1={ab,b} L2={abb,bb} then L1L2= * O {ababb,abbb,abbab,bbab} O {ab,b,abb,bb} O {ababb,abbb,babb,bbb} O {abbab,abbb,bbab,bbb}SEE MORE QUESTIONS