MRU: We assume a horizontal movement. If we graph the horizontal component of velocity as a function of time, what kind of trend (increasing linear, constant linear, upward concave, etc.) would we expect and why? Justify your answer.
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- Check Your Understanding Verify that vector v V obtained in Example 2.14 is indeed a unit vector by computing its magnitude. If the convoy in Example 2.8 was moving across a desert flatland—that is, it the third component of its velocity was zero—what is the unit vector of its direction of motion? Which geographic direction does it represent?At one point in space, the direction of the electric field vector Is given In the Cartesian system by the unit vector . If the magnitude of the electric field vector is E=400.0V/m , what are the scalar components , and of the electric field vector at this point? What is the direction angle of the electric field vector at this point?Suppose you walk 18.0 m straight west and then 25.0 m straight north. How far are you from your starting point? What is your displacement vector? What is the direction of your displacement? Assume the +x -axis is horizontal to the right.
- Please help answer this ques tion As soon as possible. Thanks! If possible within tle rext hour Suppose thet tle vectors i, jip and a, are all unit vectors and the angle 9 = 335° Find the cartesian vector form of F= (105E + 46j)N with respect to tle uv-system ot axes.kimming lai right-na ne lake, A saliboat is OSs a lad ke witrn a constant aCceler lon. ituation, we are using a systeri wi re the X2 plane is in plane positive y direction is vertically upward. All angles below are measured in the xz plane, counterclockwise from the positive x direction when view from above the lake (that is, from a point on the positive y axis). (Use a standard rectangular coordinate system where +x is to the right, +y is vertically upward, and +z is toward you. ) The sailboat's acceleration is 0.583 m/s2 at an angle of 210° for a 4.00 s time interval. At the start of this interval (noted as t = 0), it is moving with a velocity of 1.77 m/s at 30.0° and is at the position 29.7 m at 160°. Determine the following (in vector notation) for the sailboat at t = 4.00 s. (Express your answer in vector form.) (a) the position vector r(t = 4 s) (b) the velocity vector v(t = 4 s) = m/s (c) the acceleration vector a(t = 4 s) = m/s?I need to find the angle of projection for the maximum range. I have the following information: angle (degrees) and average range (cm). Here are two angles and the range for each. Angle Average Range (cm) 10 146.5 45 272.5 I think that I use this formula but I am not for sure. R=(V20 sin 2 theta)/g Can you help me figure this out so that I can do the rest of the angles and ranges.
- iteo e me cke NUMERICAL PROBLEMS Suppose, in a rectangular coordinate system, a vector A has its tail at the point a(-2,-3) and its tip at b(3, 9).Determine the distance between these two points. nead (Ans: 13 Units) 2. A certain corner of a room is selected as the origin of a rectangular coordinate system. If an insect is crawling on an adjacent wall at a point having coordinates (2,1), where the units are in metres, what is distance of the insect from this corner of the room? s. The ent dire (Ans: 2.2m) ved What is the unit vector in the direction of the vector A=4i+3j? (41+3 )) (Ans: on a magn object Two particles are located at r, = 3 i+ 7j and r2 =-2i +3j respectively. Find both the magnitude of the vector (r2.r)and its orientation with respect to the x-axis. [Ans: 6.4,219) If a vector B is added to vector A, the result is 6i + j. If B is subtracted from A, the result is -4 i+7 j. What is magnitude of vector A? (Ans: 4.1) ould th 6 Given that A =2 i+3j and B = 3 i-4 j, find the…I dont understand how to do this Using your FBD, derive an expression for tan θ in terms of FCoulomb and Fgravity, whereθ is half of the angle between the two pieces of tape at the apex of the tent shape. Hint:r is the length of the side of a right triangle opposite angle θ, and L is the hypotenuse ofthis triangle.3. This one is tougher! Consider y' the vector A in the figure to the right, making an angle 0 with re- spect to the x and y axes. that, if the length of the vector is = A, the components in this co- ordinate system are given by Show Ay O А, A cos e A sin 0 Ax Now, suppose you rotate the coordinate system by an angle d, so that the vector now makes an angle a with respect to the x' and y' axes. Show that the new components can be written in terms of the old ones as A cos A, sin d = -A, sin 0 + A cos ). A4 A A. That is, the length of the arrow Finally, show that the length of the vector doesn't change if we turn our heads and look at it sideways.
- Vhich of the following statements concerning vectors and scalars is FALSE? O A vector quantity may either be positive or negative. O Component method is used to add vectors with complex directions. O Two vectors can be added like real numbers only if they have direction. A scalar quantity may either be positive or negative.Solve the following problem using analytical techniques: Supponn you walk 16.0 m straight west and then 25.5 m stralght north. How far are you from your starting point, and what is the compass direction of a line connecting your starting point to your final position? (I you represent the two Ings of the walk as vector displacements A and B, as in the figurn hrlow, then this problem asks you to find their sum R AB. Give the direction in degrees north of west.) A +B-R N ROne newly discovered light particle has a mass of m and property q. Suppose it moves within the vicinity of an extremely heavy (fixed in place) particle with a property Q and mass M. When the light particle is xi distance from the heavy particle, it is moving directly away from the heavy particle with a speed of vi. a) What is the lighter particle's speed when it is xf away from the heavy particle? Amım2 Consider a new expression for gravitation potential energy as: PEgrav where A is a constant, m1 and m2 are the masses of the two objects, and r r is the distance between them. Moreover, the new particle has an additional interaction with the heavy particle through the following force expression Ob 4TTE, p2 1 Fnew where Eo is a constant that is read as epsilon subscript 0, q and Q are their new properties, r is the distance between the new particle and the heavy particle. Solution: We may solve this using two approaches. One involves the Newton's Laws and the other involving Work-Energy…