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- 1000- 500- 8. 10How to calculate reproduction numberLength of life (hours) 1,000–1,199 The following table gives the length of life of 400 radio tubes: No of Radio tubes 55 No. of Radio tubes Length of life (hours) 12 2,000-2,199 1,200–1,399 30 2,200-2,399 36 1,400–1,599 65 2,400-2,599 25 1,600–1,799 78 2,600-2,799 9. 1,800–1,999 Calculate (i) the average length of life of a radio tube, (ii) the standard deviation of the length of life of a tube and (iii) the percentage number of tubes where length of life of a tube falls within X + 20. 90
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- The table below contains the periodontal status of individuals and their sex. Periodontal status refers to gum disease where individuals are classified as either Healthy, have Gingivitis, or have Periodontal Disease (Perio). Female Male Total Healthy 2108 1124 3232 Gingivitis 1582 937 2519 Perio 873 931 1804 Find Pr{Gingivitis). If necessary, round your answer to 3 places after the decimal. Total 4563 2992 7555Number 10- 0.2, 0.5, 0.8,...Time (sec) Refer to the table summarizing service times (seconds) of dinners at a fast food restaurant. How many individuals are included in the summary? Is it possible to identify the exact values of all of the original service times? Frequency 60–119 120–179 21 180–239 15 240–299 1 300–359 ..... individuals are included in the summary. (Type a whole number.) Is it possible to identify the exact values of all of the original service times? O A. No. The data values in each class could take on any value between the class limits, inclusive. B. No. The frequency distribution tells nothing about the data values that fall below the lowest class limit or above the highest class limit. C. Yes. The data values in each class are spread evenly across the full length of the class. D. Yes. The data values in each class are equal to the corresponding class midpoint.
