Machines that have the following costs are under consideration for a robotized welding process. Using an interest rate of 10% per year, determine which alternative should be selected on the basis of a present worth analysis? Machine X Machine Y First cost, $ -200,000 -400,000 Annual operating cost, $ per year -40,000 -50,000 Salvage value, S 80,000 90,000 Life, years 3 6 Solution: PW Machine X- S (Use the right sign) PW Machine Y= $ (Use the right sign) So, the best alternative is Machine
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- You have been asked to evaluate two alternatives, X and Y, that may increase plant capacity for manufacturing high-pressure hydraulic hoses. The parameters associated with each alternative have been estimated. Which one should be selected on the basis of a present worth comparison at an interest rate of 13% per year? Why is yours the correct choice? Alternative First Cost X $-45,000 Maintenance cost, per $-9000 Year Salvage Value $1,000 Life 5 years Y $-55,000 $-4000 $6,500 5 years The present worth of alternative X is $ 13888 and that of alternative Y is $ 44459.4 Alternative X is selected by the company.Compare the machines below using present worth analysis at i10% per year and find which one should be selected Machine Y First Cost Operating Cost Savage Lfe cycle Machine X 20.000 3.000 3.000 3years Firat Cost 30.000 .000 Annuel Operating Cost Salvage Life cycle 3.000 6 yoarsYou have been asked to evaluate two alternatives, X and Y, that may increase plant capacity for manufacturing high-pressure hydraulic hoses. The parameters associated with each alternative have been estimated. Which one should be selected on the basis of a present worth comparison at an interest rate of 10% per year? Why is yours the correct choice? Alternative First Cost Maintenance cost, per Year Salvage Value Life X $-25,000 $-8000 $1,000 5 years Y $-55,000 $-2000 $2,000 5 years and that of alternative Y is $1 The present worth of alternative X is $. Alternativ (Click to select) is selected by the company.
- A manufacturing company is trying to decide between the two machines shown below. Determine which machine should be selected on the basis of rate of return. Assume the MARR is 20% per year. Machine A Machine B Initial Cost, $ -18,000 -35,000 Annual operating cost, $/year -4,000 -3,600 Salvage value, $ 1,000 2,700 Life, years 3 6Will save onse, Question 9 Two processes can be used for producing a polymer that reduces friction loss in engines. Which process should be selected the LCM, at an interest rate of 10% per year? Answer the below questions to select the best Option. Process A Process B First cost, $ 885,128 1,250,000 Annual operating cost, $ per 82,968 32,000 year Salvage value, $ 80,000 130,000 Update cost at year 2, $ 15,000 Life, years 4. PW for Process BDEmerson Electric manufactures compressors for air conditioners. It needs replacement equipment to improve one of its manufacturing lines. Select between two options using the MARR of 14% per year and a future worth analysis for the expected use period. What are the future values of each option? Option First cost, S A B -64,000-76,000 -16,000-22,000 AOC, $ per year Expected salvage value 8,000 11,000 Expected use, years 3 6
- Which process line should be built for a new chemical? The expected market for the chemi- cal is 20 years. A 9% rate is used to evaluate new process facilities, which are compared with present worth. How much does the better choice save? First O&M Cost Cost/year Salvage Life A $18M $5M $4M 10 years В 25M 3M 6M 20 yearsThe Fence Company is setting up a new production line to create top rails. The relevant data for two alternatives are shown below. Flow Line Manufacturing Cell Installed Cost Expected Life Salvage Value Variable Cost per Top Rail Click here to access the TVM Factor Table Calculator $15,000 5 years $0 $6.00 $10,000 5 years $0 $7.00A firm is considering three mutually exclusive alternatives as a part of an upgrade to an existing transportation network. If the MARR is 10% per year, which alternative(if any) should be chosen using the IRR analysis procedure? Use trial & error and show your calculations. A B C Initial Cost 40000 30000 20000 Annual Revenue 10400 8560 7750 Annual Cost 4000 3000 2500 Salvage Value 3000 2500 2000 Useful Life 20 20 10
- From the given values below, which machine should be selected using (a) Present worth Method and (b) Future worth Method if interest rate is 10% per year? Machine A B Initial Cost (Php) Annual Operating Cost 146,000 15,000 80,000 10,000 3 220,000 10,000 75,000 25,000 Annual Revenue Salvage Value Useful Life (years) 6A company has two options. Calculate the profitability of the proposals under the return on investment method Proposal I Proposal II Automatic machine Ordinary Machine Cost 220000 60000 Estimated life 5.5 years 8 years Estimated sales p.a 150000 150000 Cost : Material 50000 50000 Labor 12000 60000 Variable overheads 24000 20000 16 hpFor the below ME alternatives, which machine should be selected based on the AW analysis. MARR=10% First cost, $ Annual cost, $/year Salvage value, $ Life, years Machine A 15000 B- AW for machine B= 8,342 4,000 Answer the below questions : Machine B 6 20,447 6,000 5,000 Machine C 10000 4,000 1,000