Let's consider a simple supported beam subjected to a triangular distributed load and a couple moment as shown in the figure below. The equation of the shear force (0 ≤ x ≤ 2m) is given by: Select one: OV (x) = -100 X² -66.7 (N) O V(x) = -200 x²-133.3 (N) O V(x) = -25 X² +8.3 (N) O V(x) = -125 X² +41.7 (N) O V(x) = -75 x² +25 (N) 2m 300 N/m 150 N.m
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- A beam with a sliding support at B is loaded by a uniformly distributed load with intensity q. Use the method of superposition to solve for all reactions. Also draw shear-force and bending-moment diagrams, labeling all critical ordinales.A fixed-end beam AB of a length L is subjected to a uniform load of intensity q acting over the middle region of the beam (sec figure). Obtain a formula for the fixed-end moments MAand MBin terms of the load q, the length L, and the length h of the loaded part of the beam. Plot a graph of the fixed-end moment MAversus the length b of the loaded part of the beam. For convenience, plot the graph in the following nondimensional form: MAqL2/l2versusbL with the ratio b/L varying between its extreme values of 0 and 1. (c) For the special case in which ù = h = L/3, draw the shear-force and bending-moment diagrams for the beam, labeling all critical ordinates.A beam ABCD with a vertical arm CE is supported as a simple beam at .1 and D (see figure). A cable passes over a small pulley that is attached to the arm at E. One end of the cable is attached to the beam at point B. The tensile force in the cable is 1800 lb. Draw the shear-Force and bending-moment diagrams for beam A BCD. Note: Disregard the widths of the beam and vertical arm and use centerline dimensions when making calculations. Repeat part (a) if a roller support is added at C and a shear release is inserted just left of C (see figure part b).
- Find expressions for shear force V and moment Mat x = 2L/3 of beam (a) in terms of peak load intensity q0and beam length variable L. Repeat for beam (b) but at x = L/2.A beam of length L is designed to support a uniform load of intensity q (see figure). If the supports of the beam are placed at the ends, creating a simple beam, the maximum bending moment in the beam is qL2/8. However, if the supports of the beam are moved symmetrically toward the middle of the beam (as shown), the maximum bending moment is reduced. Determine the distance a between the supports so that the maximum bending moment in the beam has the smallest possible numerical value. Draw the shear-force and bending-moment diagrams for this condition. Repeat part (a) if the uniform load is replaced with a triangularly distributed load with peak intensity q0= q at mid-span (see Fig. b).The simple beam ACE shown in the figure is subjected to a triangular load of maximum intensity q0= 200 lb/ft at a = 8 ft and a concentrated moment M = 400 Ib-ft at A. Draw the shear-force and bending-moment diagrams for this beam, Find the value of distanced that results in the maximum moment occurring at L/2. Draw the shear-force and bending-moment diagrams for this case. Find the value of distance a for which Mmaxis the largest possible value.
- Determine the fixed-end moments (MAand MB) and fixed-end forces (R4and Rs) for a beam of length L supporting a triangular load of maximum intensity q0(see figure). Then draw the shear-force and bending-moment diagrams, labeling all critical ordinates.Cantilever beam AB carries an upward uniform load of intensity q1from x = 0 to L/2 (see Fig. a) and a downward uniform load of intensity q from x = L/2 to L. Find q1in terms of q if the resulting moment at A is zero. Draw V and M diagrams for the case of both q and qtas applied loadings. Repeat part (a) for the case of an upward triangularly distributed load with peak intensity q0(see Fig. b). For part (b), find q0, instead of q1Two identical, simply supported beams AB and CD are placed so that they cross each other at their midpoints (sec figure). Before the uniform load is applied, the beams just touch each other at the crossing point. Determine the maximum bending moments (mab)max* and (MCD)max beams AB and CD, respectively, due to the uniform load if the intensity of the load is q = 6.4 kN/m and the length of each beam is L = 4 m.
- Find shear (V) and moment (M) at x = 3L/4 for the beam shown in Fig. a. Let MA= 24 kN m,P = 48 kN, L = 6 m, and q0= 8 kN/m. Repeat for the beam in Fig, b (first solve for the reaction moment at fixed support A).A thin steel beam AB used in conjunction with an electromagnet in a high-energy physics experiment is securely bolted to rigid supports (see figure), A magnetic field produced by coils C results in a force acting on the beam. The force is trapezoidally distributed with maximum intensity q0= 18 kN/m. The length of the beam between supports is L = 200 mm, and the dimension c of the trapezoidal load is 50 mm. The beam has a rectangular cross section with width b = 60 and height h = 20 mm. Determine the maximum bending stress max and the maximum deflection for the beam. (Disregard any effects of axial deformations and consider only the effects of bending. Use E = 200 GPa.)Beam AB has a pin support at A and a roller support at B Joint B is also restrained by a linearly elastic rotational spring with stiffness kR, which provides a resisting moment MBdue to rotation at B. Member AB has flexural rigidity EI. A moment M0acts counterclockwise at B. Use the method of superposition to solve for all reactions. Find an expression for joint rotation Ain terms of spring stiffness kR. What is Awhen kR 0? What is Awhen kR— ? What is Awhen kR= 6EI/L?