Let a. Find A -1 b. Use A x = 6 · [¹ 2]· 6₁ = [10]· 6₂ = [10]· 63 = b3 19 * = [(6),(2)] x -1 and use it to solve Ax = 6₁. to solve Ax = 6₂. [(-6), (8)] OF cr augmented matrix [A 6₁ 62 63 64] [A6₁ 62 63 64 ~[ d. From part c., what is the solution to Ax = 63? x= [(5),(7)] and 64 = H c. In fact, Ax = b; (i = 1, 2, 3, 4) can be solved by the same set of row operations, since the coefficient matrix is the same in each case. Find the reduced row echelon form of the

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 28RE
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please find part C 

Let
[10]
A
-=[1 2]· 6₁ = [0]· 6₂ = [16] 6 = [19]- and 5₁ = []
62
63
64
I
10
10
a. Find A
x
-1
and use it to solve Ax = 6₁.
[(6),(2)]
b. Use A -1
x =
to solve Ax = 6₂.
[(-6), (8)]
bį (i
1, 2, 3, 4) can be solved by the same set of row operations, since the
coefficient matrix is the same in each case. Find the reduced row echelon form of the
augmented matrix A 6₁ 62 63 64]
A 61 62 63 64
c. In fact, Ax =
=
d. From part c., what is the solution to A = 63?
x= [(5),(7)]
OF
Transcribed Image Text:Let [10] A -=[1 2]· 6₁ = [0]· 6₂ = [16] 6 = [19]- and 5₁ = [] 62 63 64 I 10 10 a. Find A x -1 and use it to solve Ax = 6₁. [(6),(2)] b. Use A -1 x = to solve Ax = 6₂. [(-6), (8)] bį (i 1, 2, 3, 4) can be solved by the same set of row operations, since the coefficient matrix is the same in each case. Find the reduced row echelon form of the augmented matrix A 6₁ 62 63 64] A 61 62 63 64 c. In fact, Ax = = d. From part c., what is the solution to A = 63? x= [(5),(7)] OF
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