Lead metal is obtained from lead sulphide through the following reaction: 2PbS(s) + 2C(s) + 3O2(g) → 2Pb(s) +2CO(g) + 2SO2(g) a) If 100g of PbS is reacted with excess C and O2, calculate the mass of lead metal obtained. b) Suppose 100 g of PbS is reacted with 4g of C and 20g O2. Find the limiting reactant for this reaction. (c)For question (b) above, calculate the mass of lead metal obtained
Lead metal is obtained from lead sulphide through the following reaction: 2PbS(s) + 2C(s) + 3O2(g) → 2Pb(s) +2CO(g) + 2SO2(g) a) If 100g of PbS is reacted with excess C and O2, calculate the mass of lead metal obtained. b) Suppose 100 g of PbS is reacted with 4g of C and 20g O2. Find the limiting reactant for this reaction. (c)For question (b) above, calculate the mass of lead metal obtained
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter3: Chemical Reactions
Section: Chapter Questions
Problem 65QRT
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Lead metal is obtained from lead sulphide through the following reaction:
2PbS(s) + 2C(s) + 3O2(g) → 2Pb(s) +2CO(g) + 2SO2(g)
a) If 100g of PbS is reacted with excess C and O2, calculate the mass of lead metal obtained.
b) Suppose 100 g of PbS is reacted with 4g of C and 20g O2.
Find the limiting reactant for this reaction.
(c)For question (b) above, calculate the mass of lead metal obtained
d) If 31.2g Pb is obtained as the yield. calculate the percentage of yield.
e) Calculate mass of oxygen is needed to produce 500g of lead metal.
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