L= { anban bab | n ≥ 0 }
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- * .gcd(91, 287) =gcd(91, 14) yes NoNeed #3 onlyWhoever must play, cannot play def subtract_square(queries): Two players play a game of "Subtract a square", starting with a positive integer. On their turn to play, each player must subtract some square number (1, 4, 9, 16, 25, 36, 49, ...) from the current number so that the result does not become negative. Under the normal play convention of these games, the player who moves to zero wins, leaving his opponent stuck with no possible moves. (In the misère version of the game that has otherwise identical rules but where you win by losing the original game, these definitions would be adjusted accordingly.) This and many similar combinatorial games can be modelled with recursive equations. This game is an example of an impartial game since the moves available to both players are exactly the same, as opposed to “partisan games” such as chess where each player can only move pieces of one colour. A game state is therefore determined by the remaining number alone, but not by which player has…
- if L1={ab,b} L2={abb,bb} then L1L2= * O {ababb,abbb,abbab,bbab} O {ab,b,abb,bb} O {ababb,abbb,babb,bbb} O {abbab,abbb,bbab,bbb}DIVISIBLE BY 3 PROBLEM: Create the following 10 x 10 ndarray. 1 4 81 ⠀ ⠀ A = ... ⠀ ⠀ 9801 100 ⠀ ⠀ ⠀ 10000- ⠀ L8281 8464 which are the squares of the first 100 positive integers. From this ndarray, determine all the elements that are divisible by 3. Save the result as div_by_3.npyEstimate the |E*| values
- L /solve/Match the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eaxDIVISIBLE BY 3 PROBLEM: Create the following 10 x 10 ndarray. 4 81 ⠀ I ⠀ 9801 10000] 41 100 ⠀ L8281 8464 which are the squares of the first 100 positive integers. From this ndarray, determine all the elements that are divisible by 3. Save the result as div_by_3.npy
- Prob 2- uint32_t arr32 [] uint16_t *ptr16 ● = Assume we have the following code: {0x11220102, 0x33440304, 0x55660506}, *ptr32 arr32; (uint16_t *) arr32; od printf("0x%x\n", *((uint8_t *)ptr32+1)); printf ("Ox%x\n", (uint8_t) * (ptr16+1)); What are the values printed out from the above code? Ox102 .Ox02 - 10Need only unique ans don't copyHEMIP INTEGER THROUGH CODEV.