j16 2j40 2llj40 224 Ω100 V/30 (--jl 2j4 2 =-j82j10 2-j10 2=j9 210Ω3Ω82le QUESTION 3Using Figure 23-24 on page 688 of your textbook, calculate the magnitude of the voltage across the 18 ohm capacitor.O 14V RMSO 8.5V RMSO 34V RMSO 23V RMSQUESTION 4Using Figure 23-24 on page 688 of your textbook, calculate the magnitude of the current through the j9 ohm inductor.O 2.8A RMSO 11.1A RMSO 850mA RMSO 6.3A RMS

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Answered: j162 j40 2g j40 2 24 2 DO V/30 キーji2 j4…

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j162 j40 2g j40 2 24 2 DO V/30 キーji2 j4 2 =-0 -j10 2= j9 2 10Ω 32 82 ee

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

j16 2
j40 2
ll
j40 2
24 Ω
100 V/30 (
--jl 2
j4 2 =-j82
j10 2
-j10 2=
j9 2
10Ω
3Ω
82
le

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