i,(t) 10 Ω 10 Ω vo(t) (+ :50 mF 2 Η ll
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Find the transfer function Vo(ω)∕Ii(ω) for the circuit in Fig. 14.7. Obtain Practice Problem 14.2
its zeros and poles.
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- R = 470 L₁ = 47 mH www 000 ZT voo L₂ = 200 mH (c) For the circuit above, the time domain form of the voltage waveform is v(t) = 22 V sin(6161t). determine the total impedance ZT and the determine the total current IT. (Current units are in milliamperes not amperes. Include leading zeros. (example: 0.312A) Do not shift the angles.) Q+j ZT= IF mAz C = 0.1 μF ΩThe voltage and current of an element are i(t) = 3.cos(1000t + 10°) V(t) = 6.cos(1000t – 80°) The element is Select one: a. resistor and capacitor (R and C) b. resistor R c. Inductor L d. Capacitor C2. Given: v(t) = 325.269 sin( 376.991t + 36.87 ) V Find : e. V when t = 5us f. V when o = 30° g. The first angle after = 0 when V = -100V h. The first time after t 0 when V = -100V Answer: e. V = 195.652 V f. V= 299.126 V g. 0 = 161.035 h. t= 7.455 msec
- The signal V1=100 cos(500t - 30°) and the signal V2=20 sin (500t +45°) compared in phase would be a) V1 15° ahead of V2 b) V1 75° behind V2 c) V2 15° ahead of V1 d) None of the aboveA linear network has a current input 4cos (cot+ 20°) A and a voltage output 10 cos(o t+110) V. What is the value of the admittance? O 25 e None of the answers O 0.59+98 O 0.4jtermining the impedance and current of the system, the voltage across the resistor, and the voltage across the inductor. Could you please forward the response as a print of a handwritten answer? I got these two answers earlier. Which of them would be correct Impedance Z= (1000 + j 90.836) ohm Current I= 0.219∠-5.19° A Voltage across resistor VR = 219.097∠-5.19° V Voltage across inductor VL = 165.195∠84.81° V Impedance will be Z= 1004.052 ∠ 5.12° Current will be i = 0.221 ∠ -5.19° A. Volatge across resistor will be VR = 211.9∠ -5.19° V Volatge across inductor will be VL = 165.12 ∠ 84.81°V
- a. The following 40Ω capacitive reactance and 60Ω inductive reactance are in series with a 30Ω resistor in a circuit. The applied voltage is 80mV. Find the total impedance and the power factor of the circuit. Draw the circuit and find the real power that is going through the circuit. c. A signal generator generated a signal according to the function below. Calculate the strength of the signal: g(t) = cos2t – sint 0 ≤ t ≤ π100 Ω mu +100 Hz 40 V L1 0.2 H L2 0.8 H 8. What's the impedance of the circuit shown in the figure? A. 60.23 0 B. 141.76 0 C. 70.88 Q D. 285.15 (Given: L1 = 17 mHL2 = 21 mHL3 = 0.014 HL4 = 11981 mHL5 = 89 uH Calculate the total inductance of the circuit, LT.
- Addition of sinusoidal signals Calculate the phase indicator net using y3(t): y1(t) + y2(t) wheny1(t): 2cos (l20 * pi * t - pi / 3)y2(t): 0.5cos (I20 * pi * t + pi / 7)Enter an answer in the form y3(t): Acos (ω*t+Φ)dy +y coi(x) = csc(x) dy The following DE sin(x)- +y cos(x) =1 can written as Standard form of Linear in y as: %3D xp None of These. sin(x) +y cos(x) = 1 dx %3D +y cot(x) = csc(x) O dx %3D dy sin(x)Y +y cos(x) =0 xp dy 1 +y cos(x) = dx %3D sin(x)-Bolum 2- Onceki Gibi z PEE ind the time constant and sapasitance value (C) of a simple RC çiucuit ku using is SUTTent vs. time graph gven below (Here: Suppose again student number unteget generation case. R= 150 k). 150 140 RC current 130 120 110 100 90 80 70 60 50 40 30- 20 10 20 40 60 80 100 120 140 160 180 200 t (s) DOdak 20:18 27.05.2021