Inventory Database:Customers(custid, custName, address, phone, creditLimit)Orders(orderNo, orderDate, totalAmount, custID).products(prodNo, prodName, unitPrice)Includes(ordan No, prodNo, ordered Qantity).The primary keys are underlined. The referential integrity constraints are as follows:• the column custID of relation Orders that references table Customers,• the columns orderNo of relation Includes that references table orders, and• the column prodNo of relation Includes that references table Products.For the Inventory Database in the reference, write the SQL command to display the ID, name, and address of the customer who placed the order number A03012022.For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac).BIUSParagraphT "SArial10pt一田田日用因AV> तं (0)I% 0QEQ>

In this question we have to write a SQL command for the to display the ID, name, and address of the…

Answered: Inventory Database: Customers(custid,…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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branch(branchhame, branch+citysassets} customer (HD, Customer name, customer street, customer city) loan loan number branch_name, amounty borrower(ID; loan_number account (account_number, branch name, balance)e depositor (HDs account number)- Figure le Consider the bank database in Figure 1, where the primary keys are underlined. Each branch might have many loans or accounts, associated with borrowers or depositors, respectively. Construct the following SQL queries for this relational database. 1. Find the name of each branch that has at least one customer who has an account in the bank and who lives in the "Harrison" city. Make sure each branch name only appears once. 2. Find the ID of each customer who lives on the same street and in the same city as customer "12345". (1) Please use "tuple variables". e (2) Please use "derived relations" or “with". 3. Find the ID of each customer of the bank who has an account but not a loan. 4. Find the total sum of all loan amounts for each branch…
//Need typed version please You are working with a database that stores information about suppliers, parts and projects. The Supply relation records instances of a Supplier supplying a Part for a Project. The schema for the database used in this question is as follows: ( primary keys are shown underlined, foreign keys in bold). SUPPLIER (SNo, SupplierName, City) PART (PNo, PartName, Weight) PROJECT (JobNo, JobName, StartYear, Country) SUPPLY (SNo, PNo, JobNo, Quantity) Provide relational algebra (NOT SQL) queries to find the following information. NOTE: You can use the symbols s, P, etc or the words ‘PROJECT’, ‘RESTRICT’ etc . do not need to try to make efficient queries – just correct ones. Where you use a join, always show the join condition. List the name of any part that was not used on a project that commenced in 2020. List the name of any part that has been supplied to all projects that commenced in 2020.
Q2: Design Database for the following scenario and Write SQL queries. Create an ERD for the following scenario. Suppose there is a grocery store near your house. Following can be considered for ERD: A grocery store may have more than one employee. A grocery store has exactly one manager. The manager has one or more sales men working under him. Grocery store has more than one portion for the products. • Each product has a barcode, name, expired date. Many customers can busy many products, but each product is bought by only one customer. Each customer will get an invoice for his /her purchase. The bill invoice has an id.
struct student { char name[20]; char studentID[10]; char phonenum [9]; char advisor [20]; float gpa; } Operations needed: addnewStudent { purpose: to create a new student in the database input: name, studentID.phonenum,advisor.gpa output: none } Name another operation besides add that we could use for our student data structure.
STORY BOOK # Id * Name * Published date o Publisher * Type Find the error in the given ERD written by write O g. Novel name is multivalued attribute Oh. Type attribute must be in AUTHOR side O i. Cardinalities of relationships are not correct AUTHOR # Id * Name * Surname o Age O a. There is a volatile attribute and it must be converted to nonvolatile attribute O b. "Published date" and "Publisher" attributes are violating 3NF O c. Name attribute cannot be used in both entities since it is not allowed to have same name O d. Name of the "STORY BOOK" must be written as "STORY_BOOK" O e. Optionality of relationship in AUTHOR side cannot be mandatory O f. "Surname" attribute can be optional
A) The following relations kind a part of a on-line database (the relations area unit self- explanatory): CUSTOMER/CLIENT/SHOPPERS/BUYERS(Cust#, CAddress, Ctown, Balance, Cname) ORDER(Order.# Date, Cust#.) ORDERLINE(Order#, Part#, Amount-Ordered) PART(Part#., Desc, Stock, Item-Class, Unit -Price) a. Design a physical ER for the above scenario. b. With respect to this relative schema, write SQL statements for the subsequent queries: 1. List the name of the client United Nations agency has placed Order 123 (i.e. Order: = 123). 2. List the names of shoppers United Nations agency in Cardiff and have ordered half 456 (i.e. Part. 456). 3. List the order numbers (Order) for orders that contain a minimum of three elements and also the quantity ordered are minimum of ten. 4. List the outline (Desc), of these elements that the typical quantity ordered is bigger than the number ordered for half .6 (Part. = 456) so as 123.(Order..123).
. Students(stulD, lastName, firstName, major, credits) Faculty (facID, name, deptName, rank) • Classes(classNumber, facID, schedule, room) • Enrolls(stulD, classNumber, grade) The primary keys are underlined. The referential integrity constraints are as follows: . the column facID of relation Classes that references table Faculty, . the column stulD of relation Enrolls that references table Students, and the column classNumber of relation Enrolls that references table Classes. The following query is intended to retrieve the number of all classes taught by John Smith in the CST department. However, this query does not work properly. There are at least two faculty members who share the name, John Smith. Briefly explain and show the corrected SQL query_ why. SELECT classNumber FROM Classes WHERE facID= (SELECT facID FROM Faculty WHERE name='John Smith' AND deptName='CST');
Alternate keys: Identify at least five keys (not already listed as PK or FK) needed by end users. These indexes would be considered Alternate or Secondary keys and are mostly used for queries and quick reporting. They may contain multiple columns.
Database Schema The schema for the Ch07_FACT database is shown below and should be used to answer the next several problems. Click this image to view it in its own tab. FIGURE P7.56 THE CH07_FACT ERD CHECKOUT PATRON PK Check Num PK Pat ID FK1 Book_Num FK2 Pat_ID Check_Out_Date Check_Due_Date Check_In_Date >0-----H- Pat_FName Pat LName Pat_Type BOOK AUTHOR PK Book_Num PK Au ID Book_Title Book_Year Book_Cost Book_Subject FK1 Pat_ID Au_FName Au_LName Au_BirthYear WRITES PK,FK1 Book Num PK,FK2 Au ID The CIS Department at Tiny College maintains the Free Access to Current Technology (FACT) library of e-books. FACT is a collection of current technology e-books for use by faculty and students. Agreements with the publishers allow patrons to electronically check out a book,
# Question 1#Using the World database, in the city table, insert a new city for the Tasmania district. The city name is ‘Devonport’, #country code is ‘AUS’, district is ‘Tasmania’ and population is 25,387. Remember, the ID is set to auto-increment #and you will not assign a value. You will insert 2 snips for this question: #a. Insert a snip of the construct used. This MUST be a snip of the code used to insert this city into the city table. #b. Run a query to display the entire new row of Devonport inserted in the City table. Insert your snip here:
J SHORTAND NOTATION FOR RELATIONAL SQL TABLES Notation Example Meaning Underlined A or A, B The attribute(s) is (are) a primary key Superscript name of relation AR or AR, BR The attribute(s) is (are) a foreign key referencing relation R As an example, the schema R(A, B, C, D, ES) S(F, G, H) corresponds to the following SQL tables: CREATE TABLE R ( A <any SQL type>, B <any SQL type>, C <any SQL type>, D <any SQL type>, E <any SQL type>, PRIMARY KEY(A), FOREIGN KEY (E) REFERENCES S(F) ); CREATE TABLE S ( F <any SQL type>, G <any SQL type>, H <any SQL type>, PRIMARY KEY(F)) EXERCISE Consider the following relational schema, representing five relations describing shopping transactions and information about credit cards generating them [the used notation is explained above]. SHOPPINGTRANSACTION (TransId, Date, Amount, Currency, ExchangeRate, CardNbrCREDITCARD, StoreIdSTORE) CREDITCARD (CardNbr, CardTypeCARDTYPE, CardOwnerOWNER, ExpDate, Limit)…
1 ACTOR PRODUCER ACTOR 1 ALSO_A_ DIRECTOR DIRECTOR PRODUCER M 2 PERFORMS_IN LEAD ROLE M b) Some actors have done a lead role in multiple movies. c) A movie can have a minimum of two lead actors. N d) Every director has been an actor in some movie. N MOVIE 1 a) There are some actors who have acted in more than ten movies. PRODUCES Assume that MOVIES is a populated database. ACTOR is used as a generic term and includes actresses. Given the constraints shown in the ER schema, respond to the following statements with True, False, or Maybe. Assign a response of Maybe to statements that, although not explicitly shown to be True, cannot be proven False based on the schema as shown. Justify each answer. N DIRECTS N

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