int num=10, k=2; int *ptrl, *ptr2, *ptr3; c++ language ptrl = ptr1 ptrl = ptrl ptr3 = 2; k; ptr2 (int *) (ptr2 ptrl; %3D ptr3 = ptr3 = ptr2 ptr3 = (int *) (ptr2 ptrl = ptrl + 2; ptrl = ptrl + k; %3D ptr1) ptrl %3D k; Valid %3D ptr1) + k; Or %3D Not valid ptr3 = ptrl + ptr2; ptr3 = (int *) (ptrl + ptr2) ptr3 = ptr3 = (int *) (ptr1 + ptr2) + k; ptrl = ptrl * 2; ptrl ptr3 = ptr2 * ptrl; ptrl = ptrl / 2 ptrl = ptrl / k; ptr3 ptrl + ptr2 + k; %3D %3D %3D = ptrl * k; %3D %3D %3D = ptr2 / ptr%; %3D

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Related questions
Question
int num=10, k=2;
int *ptr1, *ptr2, *ptr3;
San
c++ language
ptrl = ptrl
ptrl = ptrl
ptr3 = ptr2
ptr3 =
2;
k;
%3D
ptrl;
= (int *) (ptr2
ptrl)
ptr3
ptr3 =
ptr2
ptrl
k;
(int *) (ptr2
Valid
ptr1) + k;
ptrl
ptrl + 2;
Or
ptrl = ptrl + k;
ptr3 = ptrl + ptr2;
ptr3 =
Not valid
(int *) (ptrl + ptr2)
= ptrl + ptr2 + k;
(int *) (ptrl + ptr2) + k;
ptr3
ptrl =
ptrl * 2;
ptrl = ptrl * k;
ptr3 = ptr2 * ptrl;
ptrl
= ptrl / 2
ptrl = ptrl / k;
ptr2 / ptr%;
ptr3 =
Transcribed Image Text:int num=10, k=2; int *ptr1, *ptr2, *ptr3; San c++ language ptrl = ptrl ptrl = ptrl ptr3 = ptr2 ptr3 = 2; k; %3D ptrl; = (int *) (ptr2 ptrl) ptr3 ptr3 = ptr2 ptrl k; (int *) (ptr2 Valid ptr1) + k; ptrl ptrl + 2; Or ptrl = ptrl + k; ptr3 = ptrl + ptr2; ptr3 = Not valid (int *) (ptrl + ptr2) = ptrl + ptr2 + k; (int *) (ptrl + ptr2) + k; ptr3 ptrl = ptrl * 2; ptrl = ptrl * k; ptr3 = ptr2 * ptrl; ptrl = ptrl / 2 ptrl = ptrl / k; ptr2 / ptr%; ptr3 =
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