In the program below for decomposing the entered number into its prime numbers, the location of the coding mark (ss) is #include void main() (int n,2, cinson; dol if(n) { cout<<<<"\n"; nen/ goto ss;) +*; while(i); } ss:cin>>; Oss:do { Oss:int n,i=2; Oss:while(i<=n);
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- function myCompose(f,g){// TODO: return (f o g);// that is, a function that returns f(g(x)) when invoked on x.}#include <iostream> using namespace std;struct Triple{int row, col, value;}; class Matrix; class MatrixNode{friend class Matrix;friend istream& operator>>(istream&, Matrix&);private:MatrixNode *down, *right;bool head;union{MatrixNode *next;Triple triple;};MatrixNode(bool, Triple*);}; MatrixNode::MatrixNode(bool b, Triple *t){head = b;if (b){right = down = this;}else triple = *t;};class Matrix{friend istream& operator>>(istream&, Matrix&);public:~Matrix();MatrixNode*private:MatrixNode *headnode;}; Matrix::~Matrix(){// Return all nodes to the av list, which is a chain linked// via the right field.// av is a static variable pointing to the first of the av list.if (!headnode )return; // no nodes to deleteMatrixNode *x = headnode->right; headnode->right = av;av = headnode; // return headnode while (x != headnode) { // return nodes by rowsMatrixNode *y = x->right;x->right = av;av = y;x = x->next; // next row}headnode = 0;} istream&…#include <iostream> using namespace std;struct Triple{int row, col, value;}; class Matrix; class MatrixNode{friend class Matrix;friend istream& operator>>(istream&, Matrix&);private:MatrixNode *down, *right;bool head;union{MatrixNode *next;Triple triple;};MatrixNode(bool, Triple*);}; MatrixNode::MatrixNode(bool b, Triple *t){head = b;if (b){right = down = this;}else triple = *t;};class Matrix{friend istream& operator>>(istream&, Matrix&);public:~Matrix();MatrixNode*private:MatrixNode *headnode;}; Matrix::~Matrix(){// Return all nodes to the av list, which is a chain linked// via the right field.// av is a static variable pointing to the first of the av list.if (!headnode )return; // no nodes to deleteMatrixNode *x = headnode->right; headnode->right = av;av = headnode; // return headnode while (x != headnode) { // return nodes by rowsMatrixNode *y = x->right;x->right = av;av = y;x = x->next; // next row}headnode = 0;} istream&…
- //Please Fix this program #include<iostream>using namespace std;class Point{private:int x, y;public:Point() {}Point(int x1, int y1) { x = x1; y = y1; }Point(const Point &p1) {x = p1.x; y = p1.y; } // Copy constructorint getX() { return x; }int getY() { return y; }};int main(){Point p0(); // Calling Default ConstructorPoint p1(10, 15); // Calling Parameterized constructorPoint p2 = p1; // Calling Copy constructorcout << "p0.x = " << p0.getX() << ", p0.y = " << p0.getY();cout << "p1.x = " << p1.getX() << ", p1.y = " << p1.getY();cout << "\np2.x = " << p2.getX() << ", p2.y = " << p2.getY();return 0;}Consider the following code. handler () {;} main () { struct sigaction actA, actB; sigset t oldset; sigset_t addset; sigemptyset (&addSet); sigaddset (&addset,SIGUSR1); sigprocmask (SIG BLOCK, &addset,&oldset); //-- Not using oldset here actA. sa handler=handler; actA. sa flags=0; sigemptyset(&actA.sa mask) ; sigaction (SIGTERM, &actA, (struct sigaction *) 0); Select all the signals that will be blocked during the execution of handler() after the successful execution of this code. O SIGUSR1 O SIGUSR2 O SIGTERMC++ in visual studio: Implement it completely with copy constructor, overloaded assignment operator and destructor. Then, in main, type an application that creates 2 numbers, sums them, and assigns the result to a new number. for example ; Number 1 (18,32) Number 2 (15.09) - - - - - - - - - - - + Number 3 ( 33,41)
- In C++ implement the relational operators (<, <=, ==, !=, >, >=) in the Circle class in the code below, to order the Circle objects according to their radii. #ifndef CIRCLE_H#define CIRCLE_Hclass Circle{public:Circle();Circle(double);double getArea() const;double getRadius() const;void setRadius(double);static int getNumberOfObjects();private:double radius;static int numberOfObjects;};#endifC++ Code /////// #include <iostream> class BTNode {public:int item;BTNode *left;BTNode *right;BTNode(int i, BTNode *l=nullptr, BTNode *r=nullptr):item(i),left(l),right(r){}}; BTNode *root = nullptr; void insert(int i) {//implement code here} int main(){insert (5);insert (10);insert (1);if (root){std::cout << "root = " << root->item << std::endl;if (root->left)std::cout << "root->left = " << root->left->item << std::endl;if (root->right)std::cout << "root->right = " << root->right->item << std::endl;}return 0;}C++ A robot is initially located at position (0; 0) in a grid [?5; 5] [?5; 5]. The robot can move randomly in any of the directions: up, down, left, right. The robot can only move one step at a time. For each move, print the direction of the move and the current position of the robot. If the robot makes a circle, which means it moves back to the original place, print "Back to the origin!" to the console and stop the program. If it reaches the boundary of the grid, print \Hit the boundary!" to the console and stop the program. A successful run of your code may look like:Down (0,-1)Down (0,-2)Up (0,-1)Left (-1,-1)Left (-2,-1)Up (-2,0)Left (-3,0)Left (-4,0)Left (-5,0)Hit the boundary! or Left (-1,0)Down (-1,-1)Right (0,-1)Up (0,0)Back to the origin! About: This program is to give you practice using the control ow, the random number generator, and output formatting. You may use <iomanip> to format your output. You may NOT use #include "stdafx.h".
- PROGRAMMING LANGUAGE: C++ // vectors: overloading operators example#include <iostream>using namespace std;class counter{private:int count;public:counter():count(0){}counter(int c):count(c) {} int get_count(){return count;} counter operator++ (int){return counter(count++); } counter operator-- (int){return counter(count--);}};int main(){counter c1, c2, c3;c1++;c2--;cout<<'\n'<<c1.get_count();cout<<'\n'<<c2.get_count();cout<<endl;c3 = c1++;cout<<'\n'<<c1.get_count();cout<<'\n'<<c3.get_count();getch();return 0;} Go through the above code and write the output of the given code segment. counter c1(5), c2(10), c3;c3=c1++;c2=--c3;;cout<<”\n”<<c1.get_count();cout<<”\n”<<c2.get_count();cout<<”\n”<<c3.get_count();Course: Data Structure and Algorithims Language: Java Kindly make the program in 2 hours. Task is well explained. You have to make the proogram properly in Java: Restriction: Prototype cannot be change you have to make program by using given prototype. TAsk: Create a class Node having two data members int data; Node next; Write the parametrized constructor of the class Node which contain one parameter int value assign this value to data and assign next to null Create class LinkList having one data members of type Node. Node head Write the following function in the LinkList class publicvoidinsertAtLast(int data);//this function add node at the end of the list publicvoid insertAthead(int data);//this function add node at the head of the list publicvoid deleteNode(int key);//this function find a node containing "key" and delete it publicvoid printLinkList();//this function print all the values in the Linklist public LinkListmergeList(LinkList l1,LinkList l2);// this function…C++ ProgrammingActivity: Deque Linked List Explain the flow of the main code not necessarily every line, as long as you explain what the important parts of the code do. The code is already correct, just explain the flow. SEE ATTACHED PHOTO FOR THE PROBLEM INSTRUCTIONS int main(int argc, char** argv) { DLLDeque* deque = new DLLDeque(); int test; cin >> test; //Declarations int tempnum; int num; int sum; int count; bool addfirst = false; bool addlast = false; bool remfirst = false; bool remlast = false; switch (test) { case 0: //Implementation do{ cin >> num; if(num == 0){ break; } //Reset tempnum = num; count = 0; sum = 0; addfirst = false; addlast = false; remfirst = false; remlast =…