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In order to reach equilibrium PCI5(g) must be consumed. In order to reach equilibrium K, must increase. In order to reach equilibrium PCI3 must be produced. Qc is greater than Kc. The reaction is at equilibrium. No further reaction will occur.

In order to reach equilibrium PCI5(g) must be consumed. In order to reach equilibrium K, must increase. In order to reach equilibrium PCI3 must be produced. Qc is greater than Kc. The reaction is at equilibrium. No further reaction will occur.

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter14: Chemical Equilibirum
Section: Chapter Questions
Problem 14.19QP: During an experiment with the Haber process, a researcher put 1 mol N2 and 1 mol H2 into a reaction...
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which of the following is true?
1. In order to reach equilibrium PCI5(g) must be consumed . 2. In order to reach equilibrium Kc must increase. | 3. In order to reach equilibrium PCI3 must be produced. 4. Qc is greater than Ke. 5. The reaction is at equilibrium. No further reaction will occur.
Transcribed Image Text:1. In order to reach equilibrium PCI5(g) must be consumed . 2. In order to reach equilibrium Kc must increase. | 3. In order to reach equilibrium PCI3 must be produced. 4. Qc is greater than Ke. 5. The reaction is at equilibrium. No further reaction will occur.
Consider the following reaction where K. = 1.20x10-2 at 500 K: PCI5 (g) = PCI3 (g) + Cl2 (g) A reaction mixture was found to contain 0.112 moles of PCI5 (g), 2.42x10-2 moles of PCI3 (g), and 4.24×102 moles of Cl2 (g), in a 1.00 liter containe
Transcribed Image Text:Consider the following reaction where K. = 1.20x10-2 at 500 K: PCI5 (g) = PCI3 (g) + Cl2 (g) A reaction mixture was found to contain 0.112 moles of PCI5 (g), 2.42x10-2 moles of PCI3 (g), and 4.24×102 moles of Cl2 (g), in a 1.00 liter containe
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