In activated sludge system, SRT is governed by
Q: 4-Always the total suspended solids value will be the total solids value. --- --- 5-High total…
A: As per our company guidelines we are supposed to answer only first 3️⃣ sub-parts. Kindly repost…
Q: A complete mix activated sludge secondary treatment plant has an effluent standard of 30 mg/L SS and…
A: Generally the value of the Soluble BOD is given in ProblemsAnd for activated sludge process consider…
Q: Q/ A wastewater treatment use an activated sludge process for secondary treatment of 10000 m/day for…
A: Inflow Rate (Q) = 10000 m3/dayInitial BOD (S0) = 150 mg/L =150×10-610-3 kgm3 = 0.15 kg/m3Soluble…
Q: P.C. V, X, S S.C. Qs Xg, Sp Act. Sludge Basin RAS Q, S, Xp WAS Qw, Sun Xw
A: 1. V=5222 m3 2. Qw=121.8 m3/day 3. Qe=25798.2 m3/day 4. t=4.8 hours
Q: Which condition would require decreasing the mixing speed in the slow mixing tank? * Warm inlet…
A: Introduction : Prior to sludge thickening or dewatering, slow mixing or flocculation tanks are used…
Q: A groundwater sample was found to contain 500 mg/L total dissolved solids (TDS). TDS (in %) present…
A: TDS is the measure of sudpended and dissolved solid in water. It is generally measured in mg/l or…
Q: A water sample is tested to have an alkalinity of 300 mg/L as CaCO3. The Ca^2+ concentration is 120…
A:
Q: An activated sludge plant treating a flow of 25 L/s has an aeration basin volume of 450 m³ and…
A:
Q: A solids analysis is conducted on a domestic wastewater. The followin; the 'dry sample' is obtained…
A: The different types of solids or impurities in the water are Suspended solids The solids whose…
Q: The moisture content of a sludge is 95% with a volume of 1000 m3. If the volume of dewatered sludge…
A:
Q: A complete-mix anaerobic digester is used to treat the sludge from primary sedimentation tank. The…
A: 1. We know that ; Volatile solids = 1000 * SG12 Where ; SG = Specific gravity = 1.03 Volatile solids…
Q: Fresh sludge has moisture content of 99% and, after thickening, its moisture content is reduced to…
A: Given- For fresh sludge- moisture content- w1=99%, For thickened sludge- moisture content- w2=96%.…
Q: The groundwater that appears on the surface is called springs.
A:
Q: Calculate chloride (mg/L as CF) content of the water sample.
A:
Q: Filamentous bacteria 1. Proliferate in low F:M ratio 2. Proliferate in high F:M ratio 3. Enhance…
A: Filamentous bacteria has following effects on waste water treatment .
Q: D- Activated sludge process consists 1. Aeration tank 2. Sedimentation tank 3. Aeration and…
A: Activated sludge process consists of Aeration and sedimentation tank.
Q: tank
A:
Q: sing alum at 23 mg/litre. No o ncentration is 37 mg/l. The efm and specific gravity of sludge is =
A:
Q: In a water treatment, the temperature of water is 20°C. The diameter of the solid particles present…
A:
Q: An activated sludge tank is 30 m long 9 m wide and has liquid depth of 4 m. The influent sewage flow…
A: Given data- Dimensions of the activated sludge tank-L=30mB=9mD=4mInfluent sewage flow Qo=3.5…
Q: Settling velocity increase with: * O Depth of the tank Temperature of the liquid Specific gravity of…
A: Given data in question Settling velocity To be discussed Settling velocity can be increased by…
Q: Q.68 An activated sludge tank is 30 m long 9 m wide and has liquid depth of 4 m. The influent sewage…
A: Given data- Dimensions of the sludge tank=30m×9m×4mInfluent sewage flow Qo=3.5 MLDBOD So=130mg/LMLSS…
Q: 100 m³ of sludge holds a moisture content of 95%. If its moisture content changes to 90%, the volume…
A: given- volume V1=100 m3moisture P1=95%moisture P2=90%
Q: In a membrane separation process, if the flow rate of the rejected stream (Qc)= 3000 m3/d and the…
A: Given: The flow rate of the rejected stream is 3000 m3/d. The recovery rate is 70%.
Q: n use sludge recycle.
A: Hi! Thank you for the question As per the honour code, We’ll answer the first question since the…
Q: An activated sludge system using CSTR with sludge recycle has an influent flow rate (Q°) of 2.5 MGD…
A: We have to determine the value of hydraulic retention time he solids retention time and activated…
Q: Microbial growth in an activated sludge system can be described by the Monod model. If the maximum…
A: µ=specific growth rate = .6 day-1 µmax=maximum value of μ = 1.2 day-1 KS=saturation constant =…
Q: QUESTION 4 phase of bacterial growth. Activated sludge runs at the O Decay Log Stationary O Lag
A:
Q: In a municipal wastewater treatment plant, the influent flow rate into a complete mixing activated…
A: it is a sludge containing a large concentrations of highly active aerobic micro organisms.…
Q: Question 6 A complete mix activated sludge secondary treatment plant has an influent BOD5 of 80…
A: Solution Given Data s0=80 mg/LS=10 mg/lQc= 5 dayskd=0.06/dx=2200 mg/ly=0.5 mg vss/mg BOD5
Q: a) An activated sludge plant with recycle is evaluating its secondary clarification system. Settling…
A: Activated sludge process: The process of removeal of suspended growth process for the solid waste…
Q: t more than 7 mg/L of soluble BOD in the effluent. The mixed liquor has a concentration of 3000 mg/L…
A:
Q: the DO meter showed a concentration of 8.8 mg/L. m RPD of 9% what is the saturation concentration c
A: Given:- concentration=8.8mg/L Maximum RPD=9% To find:- saturation concentration
Q: The raw sludge has solid content of 5% and the digested sludge has moisture content of 85%. The…
A: Given data, The raw sludge has solid content = 5% the digested sludge has moisture content = 85%.…
Q: An activated sludge plant with recycle is evaluating its secondary clarification system. Settling…
A: Step 1
Q: Water quality and characteristics discuss: 1. Organoleptic parameters 2. Nitrate 3. Solids
A: 1) Organoleptic Parameters- These are defined as the parameters in which results are obtained after…
Q: Calculate the hindered settling velocity of certain solid particles (S.G. = 2.701), having a…
A:
Q: Create a design mix per cu.m using the ACI DESIGN MIX PROCEDURE with the following parameters:
A: It is required to calculate the proportion of design mix.
Q: The pOH of a basic solution is 3.33. What is pH?
A: Given,POH of basic solution is 3.33
Q: A tank contains (1000) liter of brine with (15) kg of dissolved salt. Pure water enters the tank as…
A: Given data Volume Mass of salt Rate of pouring
Q: A wastewater treatment plant processes its mixed sludge by employing the gravity thickening followed…
A: Hazen William equation for Head loss due to friction in a pipeline hf=10.67*Q1.852*LC1.852*d4.8704…
Q: An aeration tank has an MLSS concentration of 2000 mg/L. After settling for 30 min. in a 1-L…
A: Solution; Given data; X=MLSS=2000 mg/litr=2.0 g/litr Ocupied Volume=150 ml
Q: Suppose that 1-L graduated cylinder in the figure as shown below contains a sludge of 1 percent…
A: Given data,
Q: Q2. A settling tank sludge sample is tested for solids. The sample and the dish weight (74.69) g,…
A: Given that: Weight of sample and dish, w1=74.69gWeight of dish, w2=21.2gWeight of…
Q: chanica
A: To find:- Vv
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images
- Example (Activated Sludge Process) - Completely Mixed with Recycle A completely mixed activated sludge process, treating a municipal wastewater, has a primary clarifier effluent BOD, of 135 mg/L. The design MLSS is 3590 mg/L, and the MLVSS is 80% of the MLSS. The plant permit is for an effluent BOD, of 20 mg/L and 20 mg/L suspended solids. The effluent suspended solids have a BOD, of 0.65 mg BOD, / mg suspended solids. The underflow solid concentration (MLVSS) is 10,000 mg/L. If umax = 3.0 day, Ks 60 mg/L, Y= 0.50 mg MLVSS / mg BOD, removed, ka= 0.1 day, and the influent flow is 0.25 m/sec, determine the following: 1. The required reactor detention time, 0. 2. The reactor basin volume, V, in m³. 3. The net waste activated sludge produced each day (kg/day). 4. The mass of solids (both volatile and inert) to be wasted each day (kg/day). The return sludge flow rate the recycle ratio. 6. The F/M ratio. 7 June 2021 Dr. Dawood Eisa Sachit Biological Wastewater Treatment 47An aeration basin for an activated sludge facility has the following characteristics Length = 90 ft Width = 30 ft Liquid depth = 12 ft MLSS=4,000 mg/L The raw wastewater has the following characteristics: Flow = 12 MGD BOD, = 220 mg/L Suspended solids (SS) = 250 mg/L A primary clarifier is ovided that removes 25% of the BOD, an 60% of the suspended solids The return activated-sludge flow rate is 0.8 MGD If the primary sludge solids content is 4% solids and the specific gravity is 1.0, the primary sludge volume (ft³/day) is most nearly OA. 1,500 OB. 60,000 O C.600 O D.4,500The test Carried aut en an follow. detaits sludge Somple are Weight of Dish =9.52gm Baw Sludge Sempla and duch =23 27ga Aşter Drying Clnstent) After Burning Clnstant) = 6.38gm 9.46gm %3D %3D Calculkt th percentage of total Salidl ad lloldi Solid in t cboue of cowego.
- In a municipal wastewater treatment plant, the influent flow rate into a complete mixing activated sludge system is 50 L/sec, its solid concentration MLSS is 30 mg/L, and the BODs in the influent is 245 mg/L. The MLSS concentration at the bottom of the secondary clarifier is 15,000 mg/L and 10 mg/L at the top of the |clarifier. The flow rate of returned activated sludge is 20 L/sec. a. What is the concentration of the MLSS in the activated sludge reactor (assuming that it is fully mixed and has constant concentration)? b. What is the activated sludge basin volume if the hydraulic retention time in the basin is 10 hours and the system is operated at the R/Q ratio given in the problem? |c. If the cross section of the basin is 20 m² (perpendicular to the flow), how long the basin will be? d. The plant has 96% BOD5 removal. What is the effluent BOD5? e. The flowrate of the waste activated sludge (WAS) is 0.2 L/sec. How many solids (in kg) are wasted every day through the secondary…4. All D- Activated sludge process consists of: 1. Aeration tank 2. Sedimentation tank 3. Aeration and sedimentation tankFor an activated sludge plant of capacity discharge (0.4380 m³/s). The F/M ratio is 0.200 mg/mg -d, the influent BOD5 after primary settling is 150 mg/L and MLSS is 2200 mg/L, volume of aeration tank will be Bidddida
- A WWTP with activated sludge secondary treatment receives 0.290 m / s of flow from the primary clarifier. There is a concentration of microbes in the aeration basin of 2500 mg VSS/L. The return sludge has a concentration of 11,000 mg VSS/L. The concentration soluble BOD from the primary clarifier is 200 mg BODs/L. The yield is 0.49 mg VSS/mg BOD 5. The solids residence time is 10 days. The effluent soluble BOD concentration is 5 mg BODs/L. The decay coefficient is 0.1 1/d. What is the volume of the activated sludge tank? First draw a picture of the system and label all variables.A coagulation treatment plant with a flow of 0.5 m/s is dosing alum at 23 mg/litre. No other chemicals are being added. The raw water suspended solid concentration is 37 mg/l. The effluent suspended solid concentration is 12 mg/l. Sludge content is 1% and specific gravity of sludge is 3.01. What volume of sludge must be disposed of every day.A mixed liquor sample form an activated sludge plant was settled in a one-litre measuring cylinder for 30 minutes after which time, a volume of 350 m/ of sludge was recorded. When 50 m/ of the mixed liquor were filtered through a GFC paper for the determination of MLSS the gain in weight of the paper was 0.1375 g. Determine the SVI.
- Filamentous bacteria 1. Proliferate in low F:M ratio 2. Proliferate in high F:M ratio 3. Enhance settling in the secondary clarifier 4. Cause bulking of sludge resulting in high solids concentration in the effluent O 2, 3 and 4 O 2 and 4 O 1, 3 and 4 1 and 4A secondary effluent that has "pinpoint" floc escaping over the weir indicates Select one: O A Over aeration. O B. Too low of a return sludge flow. O C. Nitrification OD. Rising sludge. O E Bulking sludgeA complete-mix anaerobic digester is used to treat the sludge from primary sedimentation tank. The sludge flowrate is 130 m3 /d and the bCOD loading is 6000 kg/d. The sludge has a solid content of 5% and a specific gravity of 1.03. Solid retention time (SRT) is 12 days and the temperature in digester is at 35 °C. Methane conversion factor at 35 °C is 0.40. Efficiency of waste utilization E is 0.65. Y = 0.06 kg VSS/kg bCOD utilized and kd = 0.02 d-1. Digester gas contains 63 percent methane. Determine the digester volume. Calculate the quantity of volatile solids and total gas produced per day in the digester.