In a series of seven steps, (S)-malic acid is converted to the bromoepoxide shown on the right in 50% overall yield. This synthesis is enantioselective-of the stereoisomers pos- sible for the bromoepoxide, only one is formed. OH COOH A (CgH1405) C (C,H1804) НООС (S)-Malic acid D →E F (C,H,OBr2) Br A bromoepoxide 3. LIAIH4, then H,O 4. TSCI, pyridine 5. NaBr, DMSO Steps/reagents: 1. CH,CH,OH, H+ 6. Н.О, СH,COOН 7. KOH 2. H+ In thinking about the chemistry of these steps, you will want to review the use of dihydropyran as an -OH protecting group (Section 16.7D) and the use of the p-toluenesulfonyl chloride to convert the -OH, a poor leaving group, into a tosylate, a good leaving group non

Organic Chemistry
8th Edition
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Chapter11: Ethers, Epoxides, And Sulfides
Section: Chapter Questions
Problem 11.24P: The following equation shows the reaction of trans-2,3-diphenyloxirane with hydrogen chloride in...
icon
Related questions
icon
Concept explainers
Question

Propose structural formulas for intermediates A through F and specify the configuration at each chiral center.

In a series of seven steps, (S)-malic acid is converted to the bromoepoxide shown on the
right in 50% overall yield. This synthesis is enantioselective-of the stereoisomers pos-
sible for the bromoepoxide, only one is formed.
OH
COOH
A (CgH1405)
C (C,H1804)
НООС
(S)-Malic acid
D
→E
F (C,H,OBr2)
Br
A bromoepoxide
3. LIAIH4, then H,O
4. TSCI, pyridine
5. NaBr, DMSO
Steps/reagents: 1. CH,CH,OH, H+
6. Н.О, СH,COOН
7. KOH
2.
H+
In thinking about the chemistry of these steps, you will want to review the use
of dihydropyran as an -OH protecting group (Section 16.7D) and the use of the
p-toluenesulfonyl chloride to convert the -OH, a poor leaving group, into a tosylate, a
good leaving group non
Transcribed Image Text:In a series of seven steps, (S)-malic acid is converted to the bromoepoxide shown on the right in 50% overall yield. This synthesis is enantioselective-of the stereoisomers pos- sible for the bromoepoxide, only one is formed. OH COOH A (CgH1405) C (C,H1804) НООС (S)-Malic acid D →E F (C,H,OBr2) Br A bromoepoxide 3. LIAIH4, then H,O 4. TSCI, pyridine 5. NaBr, DMSO Steps/reagents: 1. CH,CH,OH, H+ 6. Н.О, СH,COOН 7. KOH 2. H+ In thinking about the chemistry of these steps, you will want to review the use of dihydropyran as an -OH protecting group (Section 16.7D) and the use of the p-toluenesulfonyl chloride to convert the -OH, a poor leaving group, into a tosylate, a good leaving group non
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Catalysis and Enzymatic Reactions
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9781305580350
Author:
William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9781305080485
Author:
John E. McMurry
Publisher:
Cengage Learning