In a random sample of 85 automobile engine crankshaft bearings, 10 have a surface finish that is rougher than the specifications allow. Therefore, a point estimate of the proportion of bearings in the population that exceeds the roughness specification is ̂p = x∕n = 10∕85 = 0.12. Compute for a 95% two-sided confidence interval of p?
In a random sample of 85 automobile engine crankshaft bearings, 10 have a surface finish that is rougher than the specifications allow. Therefore, a point estimate of the proportion of bearings in the population that exceeds the roughness specification is ̂p = x∕n = 10∕85 = 0.12. Compute for a 95% two-sided confidence interval of p?
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter13: Probability And Calculus
Section13.2: Expected Value And Variance Of Continuous Random Variables
Problem 10E
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In a random sample of 85 automobile engine crankshaft bearings, 10 have a surface
finish that is rougher than the specifications allow. Therefore, a point estimate of the
proportion of bearings in the population that exceeds the roughness specification is ̂p
= x∕n = 10∕85 = 0.12. Compute for a 95% two-sided confidence interval of p?
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