II 15 b. (0.00763 x 10-28) (5.070 x 10-23) (0.0033 x 1013) C. (8.10 x 10-32)-1/2 = d. (0.08 liter atm mol-1 K-1) (760 torr atm-1) (440 K) = (1.6 x 10-2 liter)

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Chapter11: Properties Of Solutions
Section: Chapter Questions
Problem 4ALQ
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II
15
b.
(0.00763 x 10-28)
(5.070 x 10-23) (0.0033 x 1013)
C. (8.10 x 10-32)-1/2 =
d. (0.08 liter atm mol-1 K-1) (760 torr atm-1) (440 K) =
(1.6 x 10-2 liter)
Transcribed Image Text:II 15 b. (0.00763 x 10-28) (5.070 x 10-23) (0.0033 x 1013) C. (8.10 x 10-32)-1/2 = d. (0.08 liter atm mol-1 K-1) (760 torr atm-1) (440 K) = (1.6 x 10-2 liter)
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