If the objective function exposure quality of 90 changes by 65 ETV will not be 0. Should the 90 be 25 or 155
Q: Refer to Table S6.1 - Factors for Computing Control Chart Limits (3 sigma) for this problem. Twelve…
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A: Hence, the UCL and LCL are 0.2387 and 0.
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A: The correct answer is
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Q: Find Cp. What can we say about the process' capabilities?
A: Below is the solution:-
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A: Upper Specification (USL) = 1.841 gms Lower Specification (LSL) = 1.699 gms Mean = 1.77 gms Standard…
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Q: d All of the above
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A: The double sampling plan n1=200 , c1=5 n2=300 c2=7 for the lots , N=2000 LTPD=5% AQL=2%
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A: The double sampling plan n1=200 c1=5 n2=300 c2=7 for the lots , N=2000 LTPD=5% AQL=2%
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A: Mean absolute deviation The mean absolute deviation is determined by using the difference between…
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A: USL-LSL = 0.6 Standard Deviation = 0.1
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A: THE ANSWER IS AS BELOW:
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A: Given that: n1 =60 c1= 1 n2=120 c2 =2 and p=0.05
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A: Given A = 0.10 P1 = AQL = 0.8% = 0.008\ Beta = 0.05 P2 = LQL = 7.5% = 0.075
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A: It is given that USL = 25.76 + 1.95 = 27.71 mm and LSL = 25.76 - 1.95 = 23.81 mm Mean, = 25.76 mm…
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A: THe correct answer is
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Q: A quality control manager in an Omani bottling company takes 5 samples for quality control purposes.…
A: Sample means: 8.51, 8.18, 11.07, 10.03, and 10.23 Range: 3.33, 2.61,3.39,4.39,6.49 UCL = 11.95
If the objective function exposure quality of 90 changes by 65 ETV will not be 0. Should the 90 be 25 or 155
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- Please do not give solution in image formate thanku. The specification for a plastic liner for concrete highway projects calls for a thickness of 6.0 mm ± 0.1 mm. The standard deviation of the process is estimated to be 0.02 mm. The process is known to operate at a mean thickness of 6.03 mm. What is the Cp and Cpk for this process? Determine whether this process meet 3-sigma requirements, 6-sigma requirements, or doesn’t meet any requirements.2) The specification for a Lindemann’s stainless steel chimney liner requires a thickness of 7.1 mm ± 0.1 mm. The firm’s quality analyst determines that the liner process operates at a mean thickness of 7.13 mm with the standard deviation of the process being 0.02 mm. a) Calculate the upper and the lower limits for the stainless steel chimney liner. b) Calculate the Cpand Cpkfor this process. Hint: Cp = (Upper Specification Limit – Lower Specification Limit)/6sigma Cpk = minimum of [(Upper Specification Limit – Xbar)/3sigma], [(Xbar – Lower Specification Limit)/3sigma]Please answer this question What is the acceptable standard deviation range for running of quality controls?
- We want to determine the AOQ for an acceptance samplingplan when the quality of the incoming lots in percent defectiveis 1.5%, and then again when the incoming percent defective is 5%.T he sample size is 80 units for a lot size of 550 units. Furthermore,Pa at 1.5% defective levels is 0.95. At 5% incoming defective levels,the Pa is found to be 0.5. Determine the average outgoing qualityfor both incoming percent defective levels.When a robot welder is functioning properly the cylinders it produces burst (on average) at 3400 psi, with known standard deviation 100 psi. Determine the 3-Sigma mean control chart limits. Test lot sample sizes are n=4 cylinders randomly selected from the production line. a. Centerline = ____ b. Upper Limit = ____ c. Lower Limit = ____ d. What is the probability that random variation will exceed the ± 3-sigma limits ____. (four decimal places with zero before the decimal)A company making tires for bikes is concerned about the exact width of its cyclocrosstires. The company has a lower specification limit of 22.8 mm and an upper specification limit of 23.2 mm. The standard deviation is 0.15 mm and the mean is 23 mm.What is the process capability index for the process?
- Suppose that material hardness is normally distributed with a mean of 52 and a standard deviation of 1. Specification limits for hardness are from 45 to 55. What is Cp?In an acceptance sampling plan developed for lotscontaining 1,000 units, the sample size n is 85. The percentdefective of the incoming lots is 2%, and the probability ofacceptance is 0.64. What is the average outgoing qualityBill Kime's bowling ball factory makes bowling balls of adult size and weight only. The standard deviation in the weight of a bowling ball produced at the factory is known to be 0.39 pounds. Each day for 24 days, the average weight, in pounds, of 9 of the bowling balls produced that day has been assessed as follows Day 1 2 3 4 5 6 Average (lb) 9.9 9.9 10.1 10.1 99 99 Day 7 8 9 10 11 12 Average (lb) Day Average (b) 13 14 15 16 17 18 10.1 10.0 10.0 10.1 10.1 10.0 9.9 10.1 10.1 10.0 10.1 10.1 Day 19 20 21 22 23 24 Average (lb) 99 10.0 10.1 9.9 10.0 10.0 a) Establish a control chart for monitoring the average weights of the bowling balls in which the upper and lower control limits are each two standard deviations from the mean What are the values of the control limits? Upper Control Limit (UCL)=b (Round your response to two decimal places)
- In a sausage factory, quality managers are studying the compliance of the sausages with the requirements. Any sausage having pin holes, air pockets, deformation or breakage in its casings is counted as defective and total number of such defective sausages alone is noted in each shift. The following data represents the number of defective sausages in samples of 200 sausages taken from 10 shifts. Sample Defectives Percent Defective 1 40 20% 2 28 14% 3 15 8% 4 23 (a) 5 20 10% 6 21 11% 7 19 10% 8 15 8% 9 16 8% 10 17 9% Calculate the value for (a) in the table above. Calculate p-bar based on the samples above. What is the UCL and LCL for a p chart based on the data provided and a desired control level of 99.74%? Use your control limits from part b along with the data provided to draw a p-chart. Is the process in control? Why or why not? If not in control, suggest some potential reasons.The specifications for a gasket that installs between two engine parts calls for a thickness of 6.0 mm ± .2 mm. The standard deviation of the process is estimated to be 0.05 mm. The process is known to operate at a mean thickness of 6.1 mm What are the upper and lower specification limits for the gasket? What are the Cp and Cpk values for this process? Is this process capable of producing the desired part?A machine is used to fill cans of motor oil additive. A single sample can is selected every hour and the net weight of the can is obtained. Since the filling process is automated, it has very stable variability, and long experience indicates that s = 0.02 oz. The process target (process mean when in control) is 8.02 oz. A tabular cusum is being used for this process with standardized values h=4.5 and k=0.5. If the values of Cumulative sums at the end of measurement 7 were C," + = 0.030 and C,¯ = 0.0 , and measurement 8 is equal to Xg = 8.071, what will be the Cumulative sum at the end of measurement 8, that is C3 + = ? 0.041 0.071 0.051 0.046 0.061