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- Suppose that you are interested in estimating a population mean. You select a random sample of items, and compute the sample mean and the sample standard deviation. You then compute a 95% confidence interval to be LCL=28.4 - UCL=37.9. So what does that mean? It means that you are 95% confident that the unknown population mean that you are estimating is between the LCL and UCL. So what does that mean? It means that if you were to iterate this sampling process many times, say 100, and calculate 100 confidence intervals, then 95 of those intervals will contain the unknown population mean, and 5 will not. Give me an example of how CI can be used in your work. FYI I work in Endocrinology dept. Specific diabetesThe calculated chi-square value which is 0 is less than the critical value which is 5.991 (under the degree of freedom 2). What is the probability of the computed chi-square value? And is it part of the population in Hardy-Weinberg equilibrium?What is the expected genotype frequency of the homozygous recessive genotype under the Hardy-Weinberg equation P = 0.7? .49 .84 .42 0.09
- If the chi-square value is 0 under the degree of freedom 1. What could be the interpretation and does it fit in the population of Hardy-Weinberg equilibrium?Which of the following variables from the concept of Hardy Weinberg Equilibrium would you need to calculate for in order to figure out the frequency of the population of carriers in a region? O P^2 Q^2 P*QYou repeatedly draw samples ofn= 100 from a population with a mean of 75 and a standard deviation of 4.5. What sample mean corresponds to az-score of 2.00?
- [S] (mM) v0 (mM/sec) 6 150 17 250 29 260 40 360 50 350 60 400 72 403 82 425 92 430 103 442 115 455 125 450 Km and Vmax obtained from the Lineweaver-Burk plot and linear regression analysis for the data in Table 2 are 16.9 mM and 503 mM respectively. Compare these values to the values obtained Vmax = 525.3 µM/sec Km = 20.70 µM . Which method, nonlinear regression or linear regression, is more tolerant to an experimental error? Note that lower substrate concentrations, which often have the greater error, have a greater effect on the slope of the line in the Lineweaver-Burk plot.Which of the following variables from the concept of Hardy Weinberg Equilibrium would you need to calculate for in order to figure out the frequency of the population of carriers in a region? P^2 Q^2 P*Q None of the aboveIf d3= at the 99% confidence level what would be the critical value
- What does P-value indicate? In statistical analysis the results for two sets of data are presented with P < 0.01 and P<0.005. What does it mean?71 y = 23.397 + 0.65027x 70 69 68 67 66 65 64 66 68 70 72 MidParent height (x) Mean height of adult Offspring (y)A population consists of 300 individuals with the following genotypes: AA – 100 Aa – 125 aa – 75 a. What are the values of p and q? b. Is the population in Hardy-Weinberg equilibrium? Explain.