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- CASE STUDY On planet Betatron, mass is measured in bloobits and length in bots. You are the Earth representative on the interplanetary commission for unit conversions and find that 1 kg = 0.23 bloobits and 1 m = 1.41 bots. Express the density of a raisin (2 103 kg/m3) in Betatron units.In meters, what is the displacement traveled fromt = 10 sec to t = 25 sec? To correctly calculate the answer, you must determine the total area of this section. Enter your answer as an integer, not a fraction. 20 15 + 10 10 15 20 25 t(sec) -5 -10 -15 -20 v(m/sec) inHere v1 = 40mph. v2 = 297 mph. m1 = 15 oz. Then m2 is ____ oz. !!Solution is not M1V1 = M2V2!!
- Direction: Solve the problem. X2= 5000 m X1 = Om t = Os ts= 5s tz = 10s DA = ? ig = ? XA = ? A vg =? x = t) = t? -t + 2 aA =? ag =? B v = = 3r* + ++t 1. Sub-atomic particles A and B are moving in a 100-meter dash line in 10s. Particle A moves such that its displacement x in meters is given by the function x = (t? – t+ 2)meters. Meanwhile, particle B is moving at a velocity v = (3r' + - t² + t) m/s. If both particles A and B started from rest at the same time, Compute the following; a. Average velocity v of particle A and particle B in m/s in 10s trip. b. Displacement x of particle A and particle B from the starting point at t = 5s. c. Velocity v of particle A and particle B at t = 5s d. Acceleration a of particle A and particle B at t = 5s. (Hint: wcelention is the de ri vative of velocity; ainst = dv dt 2. In a graphing paper, graph the function ix = (t² – t + 2) in displacement x vs time t graph (x vs t) showing displacement x in the y-axis and time t in the x-axis. Then, graphically…3. The velocity of the body is given by V(t)=sin(xt), where the velocity is given in m/s and t is in seconds. The distance covered in meters between t=1/4 and ½ seconds is close to: A. -0.225 С. 1.2251 В. 0.225 D. 1 4. Evaluate the integral of xy with respect to y and to x, for the limits from x=0 to x=1, and the limits from y=1 to y=2. A. 7/9 C. % B. % D. 5/81. A car going 50mi/h overtakes and passes another car moving at 45mi/h. What length of the road is required for the operation? Assume that each car is 15ft long and that there is a 60ft space between them before and after passing. Taking into account the approach of a car from the opposite direction at 50mi/h, what clear length of the road is required? 2. Sam heaves a 16-lb shot straight up, giving it a constant upward acceleration from the rest of 41.0 m/s2for 64.0 cm. He releases it at 2.29 m above the ground. Ignore air resistance. (a) What is the speed of the shot when Sam releases it? (b) How high above the ground does it go? (c) How much time does he have to get out of its way before it returns to the height of the top of his head, 1.88 m above the ground?
- A stone is tossed into the air from ground level with an initial velocity of 30 m/s. Its height at time t is h(t) : 30t – 4.9t2 m. Compute the stone's average velocity ū in m/s over the time intervals [2, 2.01], [2,2.001], [2,2.0001] and [1.9999, 2], [1.999, 2], [1.99, 2]. (Use decimal notation. Give your answers to three decimal places.) Ū12,2.01] = m/s Ü12,2.001] = m/s U12,2.0001] = m/s1. A 1.35 kg object moves as function of time as follows: x=5 cos(1.27t+π/5), where distance is measured in metres and time in seconds.7. A particle moves along the x axis according to the equation x=6t, where x is in meter and t is in second, the speed of the particle is: 2 m/s 6 m/s 4 m/s 12 m/s A B D
- 3) The upward velocity of the rocket is measured with respect to time and the data is given in the following table. Velocity vs time data for a rocket Time, t(s) Velocity, V (m/s) 105.7 8. 175.2 12 278.2 We wanted to approximate the velocity profile by v(t=at*+bt+c,5sts12 Please construct the set of linear equation and solve the equation for the coefficients a, b and c in v (t).A car’s speed is 65 km/hour, What is this speed is the unit of “m/s”? Question 2 options: 12 m/s 65 m/s 1.1 m/s 18 m/sAfter Dan makes a basket, Josephine claims she can find the amount of time the ball was in the air (from the time it leave's Dan's hand to the time it enters the basket). 10 ft Josephine says she can do this by using Dan's equation ( h (t) = - 16t2 +18t + 8) and setting the equation equal to zero. Dan doesn't think Josephine's thinking is correct. Who do you agree with? Explain your reasoning using mathematical evidence. 0/10000 Word