I should be getting a postive sign. I know that the integral of my shear calculation is going to be my moment equation but I always use this to "check" myself against my work after I do my standard summation of moments about a point. I KNOW I SHOULD be getting M_2(x) = -.5x^2 + 2x + c but as you can see by my work I keep getting a "-2x". Why is this and where am I going wrong?

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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Im doing a shear and moment calculation for a problem graphically and keep getting a negative sign in my moment calculation where I should be getting a postive sign. I know that the integral of my shear calculation is going to be my moment equation but I always use this to "check" myself against my work after I do my standard summation of moments about a point. I KNOW I SHOULD be getting M_2(x) = -.5x^2 + 2x + c

but as you can see by my work I keep getting a "-2x". Why is this and where am I going wrong?
for 4428
15/4+
48
• save for shear
Sfyio
0= 20)(2)-V₂ (x)
V₂ (1) -+2
• we know √√₂ (X) = M₂ (x) :: S-*+2
•Lets confirm this w/ M₂:0
M₂ M₂(x) (+ΣM₂:0
M₂ (x)
V₂ (3)
²+2x+c²
0= -16 + 2 (4 + 2) + [(1)(*) · ()] + M₂ (x)
from Ay=21
Distribaved lood
0= -16 + 8 + 2% + X² + M₂ (x)
0= -8 +2x +²+ M₂ (1)
M₂00)-²-2x+8
when we check against SV₂ (x)
sign for '2x' is supposed to be positive
it is noted that the
Transcribed Image Text:for 4428 15/4+ 48 • save for shear Sfyio 0= 20)(2)-V₂ (x) V₂ (1) -+2 • we know √√₂ (X) = M₂ (x) :: S-*+2 •Lets confirm this w/ M₂:0 M₂ M₂(x) (+ΣM₂:0 M₂ (x) V₂ (3) ²+2x+c² 0= -16 + 2 (4 + 2) + [(1)(*) · ()] + M₂ (x) from Ay=21 Distribaved lood 0= -16 + 8 + 2% + X² + M₂ (x) 0= -8 +2x +²+ M₂ (1) M₂00)-²-2x+8 when we check against SV₂ (x) sign for '2x' is supposed to be positive it is noted that the
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