I am using python. The calendar year program should let the user choose how many months per row will be displayed (2-4months) but, it is not working. Pls helpterminate = Falsedays_in_month = (31,28,31,30,31,30,31,31,30,31,30,31)month_names = ('January', 'February', 'March', 'April', 'May', 'June','July', 'August', 'September', 'October', 'November', 'December')calendar_year = []month_separator = format(' ', '8')blank_week = format(' ', '21')blank_col = format(' ', '3')#prompt for years until quitwhile not terminate: #program greeting print('This program will display a calendar year for a given year') #get year year = int(input('Enter year (yyyy) (-1 to quit): ')) while (year 2099) and year != -1: year = int(input('INVALID - Enter year (1800-2099): ')) if year == -1: terminate = True else: #get number of month per row months_per_row = int(input('Enter number of months per row (2,3,4): ')) while months_per_row not in (2,3,4): months_per_row = input('INVALID - Enter number of months per row (2,3,4): ') if months_per_row == 2: first_month_rows = (0,2,4,6,8,10) elif months_per_row == 3: first_month_rows = (0,3,6,9) elif months_per_row == 4: first_month_rows = (0,4,8) #determine if leap year if (year % 4 == 0) and (not(year % 100 == 0) or (year % 400 == 0)): leap_year = True else: leap_year = False #determine day of the week century_digits = year // 100 year_digits = year % 100 value = year_digits + (year_digits // 4) if century_digits == 18: value = value + 2 elif century_digits == 20: value = value + 6 #leap year check if not leap_year: value = value + 1 # determine the first day of the month for January 1 first_day_of_current_month = (value + 1) % 7 #construct calendar for all 12 months for month_num in range(12): month_name = month_names[month_num] #init for new month current_day = 1 if first_day_of_current_month == 0: starting_col = 7 else: starting_col = first_day_of_current_month current_col = 1 calendar_week = '' calendar_month = [] #add any needed leading space for the first week of the month while current_col

Question

I am using python. The calendar year program should let the user choose how many months per row will be displayed (2-4months) but, it is not working. Pls help

terminate = False
days_in_month = (31,28,31,30,31,30,31,31,30,31,30,31)

month_names = ('January', 'February', 'March', 'April', 'May', 'June','July', 'August', 'September', 'October', 'November', 'December')

calendar_year = []
month_separator = format(' ', '8')
blank_week = format(' ', '21')
blank_col = format(' ', '3')

#prompt for years until quit
while not terminate:

#program greeting
print('This program will display a calendar year for a given year')

#get year
year = int(input('Enter year (yyyy) (-1 to quit): '))
while (year < 1800 or year > 2099) and year != -1:
year = int(input('INVALID - Enter year (1800-2099): '))

if year == -1:
terminate = True
else:
#get number of month per row
months_per_row = int(input('Enter number of months per row (2,3,4): '))
while months_per_row not in (2,3,4):
months_per_row = input('INVALID - Enter number of months per row (2,3,4): ')

if months_per_row == 2:
first_month_rows = (0,2,4,6,8,10)
elif months_per_row == 3:
first_month_rows = (0,3,6,9)
elif months_per_row == 4:
first_month_rows = (0,4,8)

#determine if leap year
if (year % 4 == 0) and (not(year % 100 == 0) or (year % 400 == 0)):
leap_year = True
else:
leap_year = False

#determine day of the week
century_digits = year // 100
year_digits = year % 100
value = year_digits + (year_digits // 4)

if century_digits == 18:
value = value + 2
elif century_digits == 20:
value = value + 6

#leap year check
if not leap_year:
value = value + 1

# determine the first day of the month for January 1
first_day_of_current_month = (value + 1) % 7

#construct calendar for all 12 months
for month_num in range(12):
month_name = month_names[month_num]

#init for new month
current_day = 1
if first_day_of_current_month == 0:
starting_col = 7
else:
starting_col = first_day_of_current_month

current_col = 1
calendar_week = ''
calendar_month = []

#add any needed leading space for the first week of the month
while current_col < starting_col:
calendar_week = calendar_week + blank_col
current_col = current_col + 1

#store month as separate weeks
if (month_name == 'February') and leap_year:
num_days_this_month = 29
else:
num_days_this_month = days_in_month[month_num]

while current_day <= num_days_this_month:

#store day of month in field of length 3
calendar_week = calendar_week + format(str(current_day),'>3')

#check if at last column of displayed week
if current_col == 7:
calendar_month = calendar_month + [calendar_week]
calendar_week = ''
current_col = 1
else:
current_col = current_col + 1

#increment current day
current_day = current_day + 1

#fill out final row of month with needed blanks
calendar_week = calendar_week + blank_week[0:(7-current_col+1) * 3]
calendar_month = calendar_month + [calendar_week]

#reset values for next month
first_day_of_current_month = current_col
calendar_year = calendar_year + [calendar_month]
calendar_month = []

# print calendar year
print('\n', year, '\n')

#number of months per row determined by months_per_row for month_num in first_month_rows:
#displays months_per_rows months in each row
for i in range(month_num, month_num + months_per_row):
print(' ' + format(month_names[i],'19'), month_separator, end='')

#display each week of months on separate lines
week = 0
lines_to_print = True

while lines_to_print:

#init
lines_to_print = False

#another week to display for 1st month in a row?
for k in range(month_num, month_num + months_per_row):
if week < len(calendar_year[k]):
print(calendar_year[k][week], end='')
lines_to_print = True
else:
print(blank_week, end='')

print(month_separator, end='')

#move to next screen line
print()

#increment week
week = week + 1

Accepted Answer

Coded using Python 3.