Hypertrophic cardiomyopathy is caused by mutations in the β-myosin heavy chain gene. One common mutation involves a change of an arginine (Arg) to a glutamine (Gln) at position 403. Using the genetic code shown above, what could the sequence of the mutant codon be? a. CAA b. CGA c. CGG d. CAC
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Hypertrophic cardiomyopathy is caused by mutations in the β-myosin heavy chain gene. One common mutation involves a change of an arginine (Arg) to a glutamine (Gln) at position 403.
Using the genetic code shown above, what could the sequence of the mutant codon be?
| a. |
CAA |
|
| b. |
CGA |
|
| c. |
CGG |
|
| d. |
CAC |
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- 3 attempts left Check my work Be sure to answer all parts. Re Consider the following sequence of DNA: 3'-AGA CCC-5'. a. What dipeptide is formed from this DNA after transcription and translation? b. If a mutation converts CCC to CCA in DNA, what dipeptide is formed? Gu c. If a mutation converts CCC to CGC in DNA, what dipeptide is formed? d. If a mutation converts CCC to GCC in DNA, what dipeptide is formed? a. b. c. d.C UUU UUC Phe UUA UCU) UCC UCA UAU UAC Tyr UGU UGC Cys Ser UAA Stop UGA Stop A UAG Stop UGG Trp UUG FLeu UCG CUU CUC CCU] СС CAU1 CAC САC His САА Gln CGU CGC Arg Leu Pro CUA CUG ССА CGA CUG J CCGJ Which of the following tRNA anticodons could theoretically base pair effectively with the codons 5'-AAU-3' and 5'-AAC-3' through third-base CAG, CGG AGU AAUASN AGC AUU AUC File A AUA ACU АСС АСА AAC FAsn AAA Ser C Thr AGA Arg A AUG Met ACG AAG Lys AGG GCU] GCC GCA GCG GGU GGC Gly GGA GAU1 GUU GUC GUA GUG Asp GACJ GAA C Val Ala A GAG Glu GGG wobble? 5'-GGG-3' OI. 5'-AUG-3' II. 5'-GUU-3' I. 5'-CAT-3' IV. 5'-AAA-3 V. Third letter UCAG UUAG A, First letterSecond letter C UUU UGU UGC. UUC Phe UUA UUG UCU UCC UCA UCGJ UAU1 UAC. Ser UAA Stop UGA Stop A Tyr Leu UAG Stop UGG Trp CAUTHIS CACS CAA GIn CAG CGU CGC Arg CCU CUU CỤC CỦA CUG J CC Leu Pro ССА CGA CCGJ CGGJ AGU Ser ACU АСС ACA AUU AAU Asn AAC AAA AUC le AGA TArg Thr AUA AUG Met ACG AAGLYS AGG GAU GUU) GUC GUA GUG GCU) GCC GCA GACASP GAA AGlu GAGS GGU GGC Gly Val Ala GGA GGG GCGJ Given the following mRNA sequence: 5' GCCCAUGUGGCGCGAGUGAUUUAA 3' Third letter UCAC UCAG UCAG UCAG 등 | First letter
- b ueton S deo4 winged dincs anel Samuels-V x r Sing https://docs.google.com/document/d/1Rd3yEXBWtvpR3nXlyNdEYqyjdDgOts37t7tMXZFQXU/edit B Untitied dxument - G X ert Format Tools Add-ons Help Last edit was seconds ago Normal text Arial 18 IUA 加 证,而,回 X ent will 1. Larry Martin and David Burnham (U of Kansas) made their 3-D model of microraptor from a mold of a single microraptor fossil. How was the hip joint of the model configured and what does this suggest about microraptor and the origin of flight? 947 AM #メ 144 240 MO 8. 6.PAYS- DASO บบบ 1 UUC UUA UUG CUU CUC CUA CUG U '} GUU GUC GUA GUG PHE LEU AUU AUC AUA AUG MET or START LEU ILE VAL UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC ACA ACG GCU GCC GCA GCG Second base SER PRO THR ALA UAC} TYR UAA UAG } STOP CAU CAC CAA CAG} AAU AAC AAA AAG J HIS GLN ASN LYS GAU ASP GAC GAG GLU UGU CYS UGC UGA} STOP UGG TRP CGU CGC CGA CGG AGU AGC AGA AGG G GGU GGC GGA GGG ARG SER ARG GLY SCAR SCAG Аpunnet squares
- Consider the mRNA sequence below. Assume that the following mRNA segment has been translated. 5'-UACCGAAUGUCU-3' Note for numbers 1 and 2: Use the three-letter abbreviation of amino acid; separate amino acids with a hyphen: do not include the stop codon. Example: ala-cys-glu 1. Using the table of the genetic code, determine the sequence of amino acids. 2. If mutation occurs by substitution of the 12th nucleotide with cytidine-5'- monophosphate, what is the resulting amino acid sequence? 3. What type of mutation occurred? Choose from same sense, missense and non-sense.I'm not sure why this structure is incorrect, can you help me draw it correctly please?Asap plz all parts
- First base U A G U UUU UUC UUA UUG CUU CUC CUA CUG Phe GUU GUC GUA GUG Leu Leu AUU AUC lle AUA AUG Met or start Val Second base C A UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC ACA ACG GCU GCC GCA GCG Ser Pro Thr Ala UAU UGU Tyr Cys UAC UGC UAA Stop UGA Stop A UAG Stop UGG Trp CAU CAC CAA CAG AAU AAC AAA AAG GAU GAC GAA GAG His Gin Asn Lys Asp G Glu CGU CGC CGA CGG AGU AGC AGA AGG GGU GGC GGA GGG Arg Ser Arg Gly UCAG UCAG ט כ с AG А U ט כ C G Third base A mutation in the DNA that codes for hemoglobin changes the sequence CTC to CAC. This will cause a change in the mRNA from (original) ? to (mutated) __?____, resulting in the addition of the amino acid, (mutated) ____?___, instead of (original) ____?_hidden message of the cide: 5' - UGAUGAUGAUGAUGCAUGCUAACGAUUCCGCAAUGUCGAUAUCAAUACGUUGACC-3'C A UUU U UUC Phe UCU UCC UCA UAU UAC UAA UAG UGU Cys U UGC Stop UGA Stop Stop UGG Trp G Tyr Ser UUA UUG Leu UCG CUU C CUC CUA CCU Leu ccc CCA CCG CAU CAC CAA His CGU CGC CGA CGG Pro Arg 1st Gin CUG CAG 3rd letter AUU A AUC AUA AUG ACU AAU AAC Ser u letter C Asn AGU AGC AGA AGG lle ACC Thr ACA AAA AAG Lys Arg Met ACG GUU G GUC GUA GUG GCU GCC GCA GCG GAU GAC GAA GAG Asp GGU GGC GGA GGG Val Ala Gly Glu Not all of the following ingredients are necessary for an in vitro translation reaction. Which one would you leave out? A ssDNA template O Cell sap containing ribosomes poly(U) O 14C-Phe