Hydrogen sulfide gas (H₂S, 34.08 g/mol) can be produced from the reaction of aluminum sulfide (150.2 g/mol) and water (18.02 g/mol) according to the following reaction equation: Al,S,(s) + 6H₂O()→3 H₂S(g) + 2 Al(OH), (s) If 65.0 g of Al2S3 reacts with excess H₂0 at 90.0°C and 0.987 atm, what volume of H₂S gas will be produced? a) 39.2 L Ob) 44.3 L Oc) 14.8 L d) 13.1 L e) 1.30 L

Chemistry for Engineering Students
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Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter4: Stoichiometry
Section: Chapter Questions
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Hydrogen sulfide gas (H₂S, 34.08 g/mol) can be produced from the reaction of
aluminum sulfide (150.2 g/mol) and water (18.02 g/mol) according to the following
reaction equation:
Al,S,(s) + 6H₂O()→3 H₂S(g) + 2 Al(OH), (s)
If 65.0 g of Al2S3 reacts with excess H₂0 at 90.0°C and 0.987 atm, what volume of
H₂S gas will be produced?
a) 39.2 L
Ob) 44.3 L
Oc) 14.8 L
d) 13.1 L
e) 1.30 L
Transcribed Image Text:Hydrogen sulfide gas (H₂S, 34.08 g/mol) can be produced from the reaction of aluminum sulfide (150.2 g/mol) and water (18.02 g/mol) according to the following reaction equation: Al,S,(s) + 6H₂O()→3 H₂S(g) + 2 Al(OH), (s) If 65.0 g of Al2S3 reacts with excess H₂0 at 90.0°C and 0.987 atm, what volume of H₂S gas will be produced? a) 39.2 L Ob) 44.3 L Oc) 14.8 L d) 13.1 L e) 1.30 L
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