how would doubling the concentration of HA affect the rate? Step 1: Fast, reversible HA = H+ + A- Step 2: Fast, reversible X + H+ = HX+ Step 3: Slow HX+ = products rate= k [X][HA]/ [A-]
how would doubling the concentration of HA affect the rate? Step 1: Fast, reversible HA = H+ + A- Step 2: Fast, reversible X + H+ = HX+ Step 3: Slow HX+ = products rate= k [X][HA]/ [A-]
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter7: Reaction Rates And Chemical Equilibrium
Section: Chapter Questions
Problem 7.83P
Related questions
Question
how would doubling the concentration of HA affect the rate?
Step 1: Fast, reversible HA = H+ + A-
Step 2: Fast, reversible X + H+ = HX+
Step 3: Slow HX+ = products
rate= k [X][HA]/ [A-]
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