How to proof the formula "energy of photon" E (kJ/mol ) = 120000/lambda (nm)

University Physics Volume 3
17th Edition
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:William Moebs, Jeff Sanny
Chapter6: Photons And Matter Waves
Section: Chapter Questions
Problem 76P: What is the momentum of a 589-nm yellow photon?
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How to proof the formula "energy of photon" E (kJ/mol
) = 120000/lambda (nm)
Transcribed Image Text:How to proof the formula "energy of photon" E (kJ/mol ) = 120000/lambda (nm)
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