How many milliliters of 2.5M benzoic acid need to be added to 500. mL of a solution already contains 6.00 grams of sodium benzoate, if you want the final pH to be 4.55? Ka for benzoic acid =6.28x10^-5   (B)if you add 16 grams of sodium benzoate to 4.55 grams of benzoic acid to a 1.00 liter container of water, what is the pH of this solution?   (c)how many grams of potassium nitrite need to be added to 250.0 mL of a 0.1500 M HNO2 solution to produce a final buffer at pH=3.65? Ka for HNO2=4.5x10^-4

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