How many grams of KBr, 119.0 g/mol, are required to prepare 0.986 moles of Br2 according to the balanced reaction? KBrO3 + 5 KBr + 6 HNO3 → 6 KNO3 + 3 Br2 + 3 H2O Report your answer with three significant figures.

Chemistry by OpenStax (2015-05-04)
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Chapter4: Stoichiometry Of Chemical Reactions
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How many grams of KBr, 119.0 g/mol, are required to prepare 0.986 moles of Br2 according to the balanced reaction?

KBrO3 + 5 KBr + 6 HNO3 → 6 KNO3 + 3 Br2 + 3 H2O

Report your answer with three significant figures.

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