How is the distance from the sun for planets in oursolar system related to the mean temperature ofeach planet? To find out, a scatterplot that relates thenatural log of the distance of each planet (includingPluto) from the sun in millions of miles and thenatural log of the mean planetary temperature inKelvin was created.In(Temperature) vs. In(Distance)6.86.66.46.265.85.65.45.24.84.64.44.2446 78.In(Distance)PredictorCoef7.9009SE CoefPConatant0.438118.030.000In Distance-0.45360.0706-6.420.004s = 0.3446R-Sq = 85.5R-8q (adj) = 83.2%Based on the scatterplot and computer output, areasonable estimate of mean temperature in Kelvinfor Saturn, which is 886.7 million miles away fromthe sun is:O 4.822 degrees Kelvin because ý = -0.4536(In886.7) + 7.9009 = 4.822.O 124.2 degrees Kelvin becausein y = -0,4536(in 886,7) + 7.9009 =4,822and e4.822 = 124.2.O 709.0 degrees Kelvin becauseIn y = - 0.4536(log 886.7) + 7.9009 =6.564and e6.564 = 709.0.O 0.05 degrees Kelvin becauseIn y = -0,4536(in 886.7) + 0.0706 = - 3.008and e-3.008 = 0.0494.In(Temperature)3.

How is the distance from the sun for planets in our solar system related to the mean temperature of each planet? To find out, a scatterplot that relates the natural log of the distance of each planet (including Pluto) from the sun in millions of miles and the natural log of the mean planetary temperature in Kelvin was created. In(Temperature) vs. In(Distance) 6.8 6.6 6.2 E 5.8 5.6 5.4 5.2 4.6 4.4 4.2 4 In(Distance) Predictor Constant Coef 7.9009 -0.4536 SE Coef 0.4381 18.03 0.000 -6.42 0.004 In Distance 0.0706 S= 0.3446 R-8g - 85.54 R-8q (adj) - 83.24 Based on the scatterplot and computer output, a reasonable estimate of mean temperature in Kelvin for Saturn, which is 886.7 million miles away from the sun is: O 4.822 degrees Kelvin because ý = -0.4536(In 886.7) + 7.9009 = 4.822. O 124.2 degrees Kelvin because iny = -0,4536(mn 86.7) +7.9009 =4,822 and et 82 = 124.2. O 709.0 degrees Kelvin because iny = -0,4536(kog 886,7) + 7.9KK9 = 6,564 and ef 564 = 709.0. O 0.05 degrees Kelvin because In y = -0,4536(in 886.7) + 0.0706 = – 3.008 and e3008 = 0.0494. 889426D O642 58642 6666 555 4444 In(Temperature)

How is the distance from the sun for planets in our solar system related to the mean temperature of each planet? To find out, a scatterplot that relates the natural log of the distance of each planet (including Pluto) from the sun in millions of miles and the natural log of the mean planetary temperature in Kelvin was created. In(Temperature) vs. In(Distance) 6.8 6.6 6.2 E 5.8 5.6 5.4 5.2 4.6 4.4 4.2 4 In(Distance) Predictor Constant Coef 7.9009 -0.4536 SE Coef 0.4381 18.03 0.000 -6.42 0.004 In Distance 0.0706 S= 0.3446 R-8g - 85.54 R-8q (adj) - 83.24 Based on the scatterplot and computer output, a reasonable estimate of mean temperature in Kelvin for Saturn, which is 886.7 million miles away from the sun is: O 4.822 degrees Kelvin because ý = -0.4536(In 886.7) + 7.9009 = 4.822. O 124.2 degrees Kelvin because iny = -0,4536(mn 86.7) +7.9009 =4,822 and et 82 = 124.2. O 709.0 degrees Kelvin because iny = -0,4536(kog 886,7) + 7.9KK9 = 6,564 and ef 564 = 709.0. O 0.05 degrees Kelvin because In y = -0,4536(in 886.7) + 0.0706 = – 3.008 and e3008 = 0.0494. 889426D O642 58642 6666 555 4444 In(Temperature)

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter7: Gravity

Section: Chapter Questions

Problem 14PQ: Since 1995, hundreds of extrasolar planets have been discovered. There is the exciting possibility...

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