The slip correction coefficient (C) for a particle with diameter 100 nm is:(assume: mean free path of air 2 = 0.066 um)(a) 1.0018G2.87037.(b) 5.0174(d) 1.0035The terminal velocity (in cm/s) for a particle with diameter 10 um and Reynolds number Re 2.5x10:a6.7x10(c) 1.7x1038.(b) 3.3x10(d) 3.3x105

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he slip correction coefficient (C) for a particle with ssume: mean free path of air 2 = 0.066 um) (a) 1.0018 ©2.8703 ne terminal velocity (in cm/s) for a particle with diam

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Properties of Fluids

The term fluid represents a type of substance that can easily change its shape under any external pressure/force and can flow. Fluids can acquire any shape in which it is stored and can resist normal stresses but cannot resist shear stress in rest condition. Whenever external shear stress is applied to fluids, it starts to flow. The fluids may be liquid or gas. Example- water, air, etc.

Question

The slip correction coefficient (C) for a particle with diameter 100 nm is:
(assume: mean free path of air 2 = 0.066 um)
(a) 1.0018
G2.8703
7.
(b) 5.0174
(d) 1.0035
The terminal velocity (in cm/s) for a particle with diameter 10 um and Reynolds number Re 2.5x10:
a6.7x10
(c) 1.7x103
8.
(b) 3.3x10
(d) 3.3x105

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